若实数xyz满足(x—z)方—4(x—y)(y—z)=0,则下列式子一定成立的是( )若实数xyz满足(x—z)方—4(x—y)(y—z)=0,则下列式子一定成立的是( )为什么?A.x+y+z=0 B.x+y—2z=0 C.y+z—2x=0 D.z+x—2y=0
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![若实数xyz满足(x—z)方—4(x—y)(y—z)=0,则下列式子一定成立的是( )若实数xyz满足(x—z)方—4(x—y)(y—z)=0,则下列式子一定成立的是( )为什么?A.x+y+z=0 B.x+y—2z=0 C.y+z—2x=0 D.z+x—2y=0](/uploads/image/z/976889-65-9.jpg?t=%E8%8B%A5%E5%AE%9E%E6%95%B0xyz%E6%BB%A1%E8%B6%B3%28x%E2%80%94z%29%E6%96%B9%E2%80%944%28x%E2%80%94y%29%28y%E2%80%94z%29%3D0%2C%E5%88%99%E4%B8%8B%E5%88%97%E5%BC%8F%E5%AD%90%E4%B8%80%E5%AE%9A%E6%88%90%E7%AB%8B%E7%9A%84%E6%98%AF%28+%29%E8%8B%A5%E5%AE%9E%E6%95%B0xyz%E6%BB%A1%E8%B6%B3%28x%E2%80%94z%29%E6%96%B9%E2%80%944%28x%E2%80%94y%29%28y%E2%80%94z%29%3D0%2C%E5%88%99%E4%B8%8B%E5%88%97%E5%BC%8F%E5%AD%90%E4%B8%80%E5%AE%9A%E6%88%90%E7%AB%8B%E7%9A%84%E6%98%AF%28+%29%E4%B8%BA%E4%BB%80%E4%B9%88%3FA.x%2By%2Bz%3D0+B.x%2By%E2%80%942z%3D0+C.y%2Bz%E2%80%942x%3D0+D.z%2Bx%E2%80%942y%3D0)
若实数xyz满足(x—z)方—4(x—y)(y—z)=0,则下列式子一定成立的是( )若实数xyz满足(x—z)方—4(x—y)(y—z)=0,则下列式子一定成立的是( )为什么?A.x+y+z=0 B.x+y—2z=0 C.y+z—2x=0 D.z+x—2y=0
若实数xyz满足(x—z)方—4(x—y)(y—z)=0,则下列式子一定成立的是( )
若实数xyz满足(x—z)方—4(x—y)(y—z)=0,则下列式子一定成立的是( )为什么?A.x+y+z=0 B.x+y—2z=0 C.y+z—2x=0 D.z+x—2y=0
若实数xyz满足(x—z)方—4(x—y)(y—z)=0,则下列式子一定成立的是( )若实数xyz满足(x—z)方—4(x—y)(y—z)=0,则下列式子一定成立的是( )为什么?A.x+y+z=0 B.x+y—2z=0 C.y+z—2x=0 D.z+x—2y=0
【题中(X-Z)少了平方,否则当X=3/2、Y=3/4、Z=3/8时满足题意,但ABCD都不成立】
令 X-Y = a ,Y-Z = b ,
则 X-Z = (X-Y)+(Y-Z) = a+b ;
已知,(X-Z)²-4(X-Y)(Y-Z) = 0 ,
即有:(a+b)²-4ab = 0 ,
则有:(a-b)² = (a+b)²-4ab = 0 ,
可得:a-b = 0 ,
即有:(X-Y)-(Y-Z) = 0 ,
所以,Z+X-2Y = 0 ,
选 D .
希望能解决您的问题.
若实数xyz满足(x—z)方—4(x—y)(y—z)=0,则下列式子一定成立的是( )若实数xyz满足(x—z)方—4(x—y)(y—z)=0,则下列式子一定成立的是( )为什么?A.x+y+z=0 B.x+y—2z=0 C.y+z—2x=0 D.z+x—2y=0
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