函数为 VO=-VI×[(R*F/2*3.14×j×R*C+F)] 用maitlab编程拟合曲线 程序如下:VI=[1,2,3,4,5,6,7];C=[2.31318,14.1402,17.9081,28.71,30.7746,86.4247,156.2];R=[19.633,4.0983,3.282,1.7222,1.1954,0.70498,0.382];F=[0.05,0.1,0.5,1,5,10,20,25,30,35,5
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![函数为 VO=-VI×[(R*F/2*3.14×j×R*C+F)] 用maitlab编程拟合曲线 程序如下:VI=[1,2,3,4,5,6,7];C=[2.31318,14.1402,17.9081,28.71,30.7746,86.4247,156.2];R=[19.633,4.0983,3.282,1.7222,1.1954,0.70498,0.382];F=[0.05,0.1,0.5,1,5,10,20,25,30,35,5](/uploads/image/z/9559262-38-2.jpg?t=%E5%87%BD%E6%95%B0%E4%B8%BA+VO%3D-VI%C3%97%5B%28R%2AF%2F2%2A3.14%C3%97j%C3%97R%2AC%2BF%29%5D+%E7%94%A8maitlab%E7%BC%96%E7%A8%8B%E6%8B%9F%E5%90%88%E6%9B%B2%E7%BA%BF+%E7%A8%8B%E5%BA%8F%E5%A6%82%E4%B8%8B%EF%BC%9AVI%3D%5B1%2C2%2C3%2C4%2C5%2C6%2C7%5D%3BC%3D%5B2.31318%2C14.1402%2C17.9081%2C28.71%2C30.7746%2C86.4247%2C156.2%5D%3BR%3D%5B19.633%2C4.0983%2C3.282%2C1.7222%2C1.1954%2C0.70498%2C0.382%5D%3BF%3D%5B0.05%2C0.1%2C0.5%2C1%2C5%2C10%2C20%2C25%2C30%2C35%2C5)
函数为 VO=-VI×[(R*F/2*3.14×j×R*C+F)] 用maitlab编程拟合曲线 程序如下:VI=[1,2,3,4,5,6,7];C=[2.31318,14.1402,17.9081,28.71,30.7746,86.4247,156.2];R=[19.633,4.0983,3.282,1.7222,1.1954,0.70498,0.382];F=[0.05,0.1,0.5,1,5,10,20,25,30,35,5
函数为 VO=-VI×[(R*F/2*3.14×j×R*C+F)] 用maitlab编程拟合曲线 程序如下:
VI=[1,2,3,4,5,6,7];
C=[2.31318,14.1402,17.9081,28.71,30.7746,86.4247,156.2];
R=[19.633,4.0983,3.282,1.7222,1.1954,0.70498,0.382];
F=[0.05,0.1,0.5,1,5,10,20,25,30,35,50];
Vo=-VI*[R*F/(2*Pi*j*R*C+F)]
P2=Polyfit(F,Vo,2);
Vo2=ployval(p2,F);
为什不对?应该怎样写才能拟合出曲线来,
拟合的曲线是幅频曲线,输出电压VO和频率F.
函数为 VO=-VI×[(R*F/2*3.14×j×R*C+F)] 用maitlab编程拟合曲线 程序如下:VI=[1,2,3,4,5,6,7];C=[2.31318,14.1402,17.9081,28.71,30.7746,86.4247,156.2];R=[19.633,4.0983,3.282,1.7222,1.1954,0.70498,0.382];F=[0.05,0.1,0.5,1,5,10,20,25,30,35,5
矩阵乘的有问题
如果就是各个对应项相乘的话
最简单就是加个循环,把你原来那句矩阵相乘标注掉,不过不知道你那里面那个j是哪来的,前面补上j的定义就可以了
for ii=1:length(VI)
VO[ii]=-VI[ii]*(R[ii]*F[ii]/(2*pi*j*R[ii]*C[ii]+F[ii]))
end
%Vo=-VI*[R*F/(2*Pi*j*R*C+F)]