英语翻译A pool cue striking a stationary billiary ball (mass= 0.25kg) gives the ball a speed of 2m/s.If the force of the cue on the ball was 25N,over what distance did this force act?如果用动能定理的话直接是k=1/2 mv^2= 0.5*0.25kg*2m/s
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![英语翻译A pool cue striking a stationary billiary ball (mass= 0.25kg) gives the ball a speed of 2m/s.If the force of the cue on the ball was 25N,over what distance did this force act?如果用动能定理的话直接是k=1/2 mv^2= 0.5*0.25kg*2m/s](/uploads/image/z/8837402-50-2.jpg?t=%E8%8B%B1%E8%AF%AD%E7%BF%BB%E8%AF%91A+pool+cue+striking+a+stationary+billiary+ball+%28mass%3D+0.25kg%29+gives+the+ball+a+speed+of+2m%2Fs.If+the+force+of+the+cue+on+the+ball+was+25N%2Cover+what+distance+did+this+force+act%3F%E5%A6%82%E6%9E%9C%E7%94%A8%E5%8A%A8%E8%83%BD%E5%AE%9A%E7%90%86%E7%9A%84%E8%AF%9D%E7%9B%B4%E6%8E%A5%E6%98%AFk%3D1%2F2+mv%5E2%3D+0.5%2A0.25kg%2A2m%2Fs)
英语翻译A pool cue striking a stationary billiary ball (mass= 0.25kg) gives the ball a speed of 2m/s.If the force of the cue on the ball was 25N,over what distance did this force act?如果用动能定理的话直接是k=1/2 mv^2= 0.5*0.25kg*2m/s
英语翻译
A pool cue striking a stationary billiary ball (mass= 0.25kg) gives the ball a speed of 2m/s.If the force of the cue on the ball was 25N,over what distance did this force act?
如果用动能定理的话直接是k=1/2 mv^2= 0.5*0.25kg*2m/s^2 = 0.5J
根据合外力所做的功等于动能 W= K ,W= fd,∴ d=k/f= 0.5J/25N =0.02m
所以移动了2cm
那如果用牛顿第二定律应该怎么做啊
英语翻译A pool cue striking a stationary billiary ball (mass= 0.25kg) gives the ball a speed of 2m/s.If the force of the cue on the ball was 25N,over what distance did this force act?如果用动能定理的话直接是k=1/2 mv^2= 0.5*0.25kg*2m/s
加速度 a = 25/0.25 = 100 m/s^2
根据 v2^2 - v1^2 = 2aS,有
2^2 - 0 = 2*100*S
S = 0.02 m
算加速度,a=F/M=25/0.25=100
初速度为0,所以末速度v*v-0=2*a*s.于是算出s=v*v/2/a=4/2/100=0.02米。