mathematics怎样计算极限limit[[sqrt[4 + 1/x - 1/x^2] - 1 + 1/x]/sqrt[1 + sin[x]/x^2],x -> -infinity];想求极限,is incomplete; more input is needed.”怎么回事?
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/28 04:32:57
![mathematics怎样计算极限limit[[sqrt[4 + 1/x - 1/x^2] - 1 + 1/x]/sqrt[1 + sin[x]/x^2],x -> -infinity];想求极限,is incomplete; more input is needed.”怎么回事?](/uploads/image/z/8014759-7-9.jpg?t=mathematics%E6%80%8E%E6%A0%B7%E8%AE%A1%E7%AE%97%E6%9E%81%E9%99%90limit%5B%5Bsqrt%5B4+%2B+1%2Fx+-+1%2Fx%5E2%5D+-+1+%2B+1%2Fx%5D%2Fsqrt%5B1+%2B+sin%5Bx%5D%2Fx%5E2%5D%2Cx+-%3E+-infinity%5D%EF%BC%9B%E6%83%B3%E6%B1%82%E6%9E%81%E9%99%90%2Cis+incomplete%3B+more+input+is+needed.%E2%80%9D%E6%80%8E%E4%B9%88%E5%9B%9E%E4%BA%8B%3F)
mathematics怎样计算极限limit[[sqrt[4 + 1/x - 1/x^2] - 1 + 1/x]/sqrt[1 + sin[x]/x^2],x -> -infinity];想求极限,is incomplete; more input is needed.”怎么回事?
mathematics怎样计算极限
limit[[sqrt[4 + 1/x - 1/x^2] - 1 + 1/x]/sqrt[1 + sin[x]/x^2],
x -> -infinity];
想求极限,is incomplete; more input is needed.”怎么回事?
mathematics怎样计算极限limit[[sqrt[4 + 1/x - 1/x^2] - 1 + 1/x]/sqrt[1 + sin[x]/x^2],x -> -infinity];想求极限,is incomplete; more input is needed.”怎么回事?
limit[[sqrt[4 + 1/x - 1/x^2] - 1 + 1/x]/sqrt[1 + sin[x]/x^2],
x -> -infinity] ;
Syntax::sntxb: Expression cannot begin with "[sqrt[4+1/x-1/x^2]-1+1/x]/sqrt[1+sin[x]/x^2]".
Syntax::tsntxi: "[sqrt[4+1/x-1/x^2]-1+1/x]" is incomplete; more input is needed.
Syntax::sntxi: Incomplete expression; more input is needed.