数学分析:construct a sequence (tn) of real numbers according to the following recursive rules:t0=0; t(n+1)=tn+(25-tn^2)/10a) show that (tn) is convergentb)compute the limit of tn as n goes to infinity谢谢!
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![数学分析:construct a sequence (tn) of real numbers according to the following recursive rules:t0=0; t(n+1)=tn+(25-tn^2)/10a) show that (tn) is convergentb)compute the limit of tn as n goes to infinity谢谢!](/uploads/image/z/6945789-21-9.jpg?t=%E6%95%B0%E5%AD%A6%E5%88%86%E6%9E%90%EF%BC%9Aconstruct+a+sequence+%28tn%29+of+real+numbers+according+to+the+following+recursive+rules%3At0%3D0%3B+t%28n%2B1%29%3Dtn%2B%2825-tn%5E2%29%2F10a%29+show+that+%28tn%29+is+convergentb%29compute+the+limit+of+tn+as+n+goes+to+infinity%E8%B0%A2%E8%B0%A2%21)
数学分析:construct a sequence (tn) of real numbers according to the following recursive rules:t0=0; t(n+1)=tn+(25-tn^2)/10a) show that (tn) is convergentb)compute the limit of tn as n goes to infinity谢谢!
数学分析:construct a sequence (tn) of real numbers according to the following recursive rules:
t0=0; t(n+1)=tn+(25-tn^2)/10
a) show that (tn) is convergent
b)compute the limit of tn as n goes to infinity
谢谢!
数学分析:construct a sequence (tn) of real numbers according to the following recursive rules:t0=0; t(n+1)=tn+(25-tn^2)/10a) show that (tn) is convergentb)compute the limit of tn as n goes to infinity谢谢!
a)0
b)设limtn=x,则x=x+(25-x^2)/5,x=5(x=-5舍去)
即limtn=5
数学分析:construct a sequence (tn) of real numbers according to the following recursive rules:t0=0; t(n+1)=tn+(25-tn^2)/10a) show that (tn) is convergentb)compute the limit of tn as n goes to infinity谢谢!
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