计算:1-tan(5π/12)tan(π/4) ------------------------------- tan(5π/12)+tan(π/4)那条横杠是分数线
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计算:1-tan(5π/12)tan(π/4) ------------------------------- tan(5π/12)+tan(π/4)那条横杠是分数线
计算:1-tan(5π/12)tan(π/4) ------------------------------- tan(5π/12)+tan(π/4)
那条横杠是分数线
计算:1-tan(5π/12)tan(π/4) ------------------------------- tan(5π/12)+tan(π/4)那条横杠是分数线
[1-tan(5π/12)tan(π/4)]/ [tan(5π/12)+tan(π/4)]
=1/tan(5π/12+π/4)
=1/tan(2π/3)
=-1/tan(π/3)
=-√3/3
计算:1-tan(5π/12)tan(π/4) ------------------------------- tan(5π/12)+tan(π/4)那条横杠是分数线
计算 tanπ/12+1/tanπ/12
计算tanπ/12 / (1-tan^2π/12)=
化简:[tan(5π)/4+tan(5π)/12]/[1-tan(5π)/12]
tan(π/12)-(1/tan(π/12))
化简:[tan(5/4)π+tan(5/12)π]/[1-tan(5/12)π]
计算 tanπ/12-tan5π/12
tan( x/2+π/4)+tan(x/2-π/4 )=2tanxtan(x/2+π/4)+tan(x/2-π/4)=[tan(x/2)+tan(π/4)]/[1-tan(x/2)tan(π/4)]+[tan(x/2)-tan(π/4)]/[1+tan(x/2)tan(π/4)]=[tan(x/2)+1]/[1-tan(x/2)]+[tan(x/2)-1]/[1+tan(x/2)]=[(tan(x/2)+1)^2-(tan(x/2)-1)^2]/[1-(tan(x
计算tanπ/12的值
求证(1)1+tanθ/1-tanθ=tan(π/4+θ) (2)1-tanθ/1+tanθ=tan(π/4-θ)
(1-tan^2π/12)/(tanπ/12)化简
tan(π/12)+1/tan(π/12)=啥?
tanπ/12-1/tanπ/12=
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