帮我解一下这个材料力学题目A tensile test uses a test specimen that has a gage length of 50 mm and an area = 200 mm2. During the test the specimen yields under a load of 98,000 N. The corresponding gage length = 50.23 mm. This is the 0.2
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![帮我解一下这个材料力学题目A tensile test uses a test specimen that has a gage length of 50 mm and an area = 200 mm2. During the test the specimen yields under a load of 98,000 N. The corresponding gage length = 50.23 mm. This is the 0.2](/uploads/image/z/6284145-57-5.jpg?t=%E5%B8%AE%E6%88%91%E8%A7%A3%E4%B8%80%E4%B8%8B%E8%BF%99%E4%B8%AA%E6%9D%90%E6%96%99%E5%8A%9B%E5%AD%A6%E9%A2%98%E7%9B%AEA+tensile+test+uses+a+test+specimen+that+has+a+gage+length+of+50+mm+and+an+area+%3D+200+mm2.+During+the+test+the+specimen+yields+under+a+load+of+98%2C000+N.+The+corresponding+gage+length+%3D+50.23+mm.+This+is+the+0.2)
帮我解一下这个材料力学题目A tensile test uses a test specimen that has a gage length of 50 mm and an area = 200 mm2. During the test the specimen yields under a load of 98,000 N. The corresponding gage length = 50.23 mm. This is the 0.2
帮我解一下这个材料力学题目
A tensile test uses a test specimen that has a gage length of 50 mm and an area = 200 mm2. During the test the specimen yields under a load of 98,000 N. The corresponding gage length = 50.23 mm. This is the 0.2 percent yield point. The maximum load = 168,000 N is reached at a gage length = 64.2 mm.
a) Determine yield strength Y,
(b) Determine modulus of elasticity E
(c) Determine tensile strength TS.
帮我解一下这个材料力学题目A tensile test uses a test specimen that has a gage length of 50 mm and an area = 200 mm2. During the test the specimen yields under a load of 98,000 N. The corresponding gage length = 50.23 mm. This is the 0.2
还是英文,不给点悬赏分啊.
a)Sy=98000/(200*10^-6)=490Mpa
b)E=FL/(elongation)*A=106.5Gpa
c)assuming volume does not change,implies 50*200=64.2*A,A=155.76mm^2,
Sut=F/A=168000/(155.76*10^-6)=1.08Gpa