matlab 试题求解五 某泵站在扬程4m,总流量在530l/s的条件下三台调速机组运行,三台机组在扬程等于4m时功率(kw)—流量(l/s)特性可表示为:N1=8.316-3.088*10-2*Q1+2.346*10-4*Q12
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![matlab 试题求解五 某泵站在扬程4m,总流量在530l/s的条件下三台调速机组运行,三台机组在扬程等于4m时功率(kw)—流量(l/s)特性可表示为:N1=8.316-3.088*10-2*Q1+2.346*10-4*Q12](/uploads/image/z/6106841-17-1.jpg?t=matlab+%E8%AF%95%E9%A2%98%E6%B1%82%E8%A7%A3%E4%BA%94+%E6%9F%90%E6%B3%B5%E7%AB%99%E5%9C%A8%E6%89%AC%E7%A8%8B4m%2C%E6%80%BB%E6%B5%81%E9%87%8F%E5%9C%A8530l%2Fs%E7%9A%84%E6%9D%A1%E4%BB%B6%E4%B8%8B%E4%B8%89%E5%8F%B0%E8%B0%83%E9%80%9F%E6%9C%BA%E7%BB%84%E8%BF%90%E8%A1%8C%2C%E4%B8%89%E5%8F%B0%E6%9C%BA%E7%BB%84%E5%9C%A8%E6%89%AC%E7%A8%8B%E7%AD%89%E4%BA%8E4m%E6%97%B6%E5%8A%9F%E7%8E%87%28kw%29%E2%80%94%E6%B5%81%E9%87%8F%28l%2Fs%29%E7%89%B9%E6%80%A7%E5%8F%AF%E8%A1%A8%E7%A4%BA%E4%B8%BA%EF%BC%9AN1%3D8.316-3.088%2A10-2%2AQ1%2B2.346%2A10-4%2AQ12)
matlab 试题求解五 某泵站在扬程4m,总流量在530l/s的条件下三台调速机组运行,三台机组在扬程等于4m时功率(kw)—流量(l/s)特性可表示为:N1=8.316-3.088*10-2*Q1+2.346*10-4*Q12
matlab 试题求解
五 某泵站在扬程4m,总流量在530l/s的条件下三台调速机组运行,三台机组在扬程等于4m时功率(kw)—流量(l/s)特性可表示为:
N1=8.316-3.088*10-2*Q1+2.346*10-4*Q12
N2=7.459-2.95*10-2*Q2+2.348*10-4*Q22
N3=8.324-2.5*10-2*Q3+1.879*10-4*Q3 2
根据调速范围,各机组流量最大、最小值为:
100
matlab 试题求解五 某泵站在扬程4m,总流量在530l/s的条件下三台调速机组运行,三台机组在扬程等于4m时功率(kw)—流量(l/s)特性可表示为:N1=8.316-3.088*10-2*Q1+2.346*10-4*Q12
function minN
A=[];B=[];Aeq=[1 1 1];Beq=[530];
LB=[100 100 100];UB=[230 250 280];
Q0=[200 200 200];
[Q,minN,EXITFLAG] = fmincon(@myfun,Q0,A,B,Aeq,Beq,LB,UB)
function N=myfun(Q)
N1=8.316-3.088*10^-2*Q(1)+2.346*10^-4*Q(1)^2;
N2=7.459-2.95*10^-2*Q(2)+2.348*10^-4*Q(2)^2;
N3=8.324-2.5*10^-2*Q(3)+1.879*10^-4*Q(3)^2;
N=N1+N2+N3;
结果:
Optimization terminated:magnitude of directional derivative in search
direction less than 2*options.TolFun and maximum constraint violation
is less than options.TolCon.
No active inequalities.
Q =
169.1705 165.6137 195.2159
minN =
29.4237
EXITFLAG =
5