2lg2+2lg2*lg5+2lg5木有得数吗
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![2lg2+2lg2*lg5+2lg5木有得数吗](/uploads/image/z/6075017-17-7.jpg?t=2lg2%2B2lg2%2Alg5%2B2lg5%E6%9C%A8%E6%9C%89%E5%BE%97%E6%95%B0%E5%90%97)
2lg2+2lg2*lg5+2lg5木有得数吗
2lg2+2lg2*lg5+2lg5
木有得数吗
2lg2+2lg2*lg5+2lg5木有得数吗
2lg2=lg4 2lg5=lg25
故原式等于lg4+lg4*lg5+lg25=lg4(lg10+lg5)+lg25=lg4*lg50+lg25
平方和1
lg2(1+lg5)+(lg5)^2
计算:(lg5)^2 +lg2 *lg5
(lg5)^2+lg5.lg2=
2lg2(lg2+lg5)+2lg5得数
(lg2)^2+lg2*lg5+(lg5)^2=
lg2*lg50+lg5*lg20-2lg5*lg2
(lg5)平方+2*lg5*lg2+(lg2)平方
(lg2)^2+lg5*lg20
(lg2)^2+lg20*lg5
(lg5)^2+lg2*lg50
3+lg5+(lg2)^2
2lg5*lg2=
=(lg5)^2+lg2×lg5+lg2 =lg5×(lg5+lg2)+lg2麻烦问一下,这是咋做的
lg5(1-lg5)+2lg5根号2+lg2(1-lg5)
2lg2+2lg2*lg5+2lg5木有得数吗
lg2^2+lg2*lg5+lg5=lg2(lg2+lg5)+lg5这个过程中,lg2的平方怎么没了?
(lg^2)2+lg2*lg5+lg5
lg5^2+lg4+lg5*lg20+(lg2)^2