化简[2sin50°+sin10°(1+√3tan10°)] √(sin²80°)尽量简单点
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![化简[2sin50°+sin10°(1+√3tan10°)] √(sin²80°)尽量简单点](/uploads/image/z/565459-43-9.jpg?t=%E5%8C%96%E7%AE%80%5B2sin50%C2%B0%2Bsin10%C2%B0%281%2B%E2%88%9A3tan10%C2%B0%29%5D+%E2%88%9A%28sin%26%23178%3B80%C2%B0%29%E5%B0%BD%E9%87%8F%E7%AE%80%E5%8D%95%E7%82%B9)
化简[2sin50°+sin10°(1+√3tan10°)] √(sin²80°)尽量简单点
化简[2sin50°+sin10°(1+√3tan10°)] √(sin²80°)尽量简单点
化简[2sin50°+sin10°(1+√3tan10°)] √(sin²80°)尽量简单点
[2sin50°+sin10°(1+√3tan10°)]•√(2sin²80°)
= [2sin50 + sin10(cos10+√3sin10)/cos10]•√2sin80
= [2sin50cos10+2sin10(cos60cos10+sin60sin10)•√2sin80/cos10
= 2[sin50cos10 + sin10cos(60-10)]•√2
= 2sin(50+10)•√2
= √6
请点击下面的【选为满意回答】按钮,
答案为根号3
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