已知α是第二象限角,tan(α-270°)=1/5 (1)求sinα和cosα的值已知α是第二象限角,tan(α-270°)=1/5(1)求sinα和cosα的值(2)求{sin(180°-α)cos(360°-α)tan(-α+270°)}/{sin(-180°-α)tan(α-270°)}的
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![已知α是第二象限角,tan(α-270°)=1/5 (1)求sinα和cosα的值已知α是第二象限角,tan(α-270°)=1/5(1)求sinα和cosα的值(2)求{sin(180°-α)cos(360°-α)tan(-α+270°)}/{sin(-180°-α)tan(α-270°)}的](/uploads/image/z/5191071-15-1.jpg?t=%E5%B7%B2%E7%9F%A5%CE%B1%E6%98%AF%E7%AC%AC%E4%BA%8C%E8%B1%A1%E9%99%90%E8%A7%92%2Ctan%EF%BC%88%CE%B1-270%C2%B0%EF%BC%89%3D1%2F5+%EF%BC%881%EF%BC%89%E6%B1%82sin%CE%B1%E5%92%8Ccos%CE%B1%E7%9A%84%E5%80%BC%E5%B7%B2%E7%9F%A5%CE%B1%E6%98%AF%E7%AC%AC%E4%BA%8C%E8%B1%A1%E9%99%90%E8%A7%92%2Ctan%EF%BC%88%CE%B1-270%C2%B0%EF%BC%89%3D1%2F5%EF%BC%881%EF%BC%89%E6%B1%82sin%CE%B1%E5%92%8Ccos%CE%B1%E7%9A%84%E5%80%BC%EF%BC%882%EF%BC%89%E6%B1%82%EF%BD%9Bsin%28180%C2%B0-%CE%B1%29cos%28360%C2%B0-%CE%B1%29tan%28-%CE%B1%2B270%C2%B0%29%EF%BD%9D%2F%EF%BD%9Bsin%28-180%C2%B0-%CE%B1%29tan%28%CE%B1-270%C2%B0%29%EF%BD%9D%E7%9A%84)
已知α是第二象限角,tan(α-270°)=1/5 (1)求sinα和cosα的值已知α是第二象限角,tan(α-270°)=1/5(1)求sinα和cosα的值(2)求{sin(180°-α)cos(360°-α)tan(-α+270°)}/{sin(-180°-α)tan(α-270°)}的
已知α是第二象限角,tan(α-270°)=1/5 (1)求sinα和cosα的值
已知α是第二象限角,tan(α-270°)=1/5
(1)求sinα和cosα的值
(2)求{sin(180°-α)cos(360°-α)tan(-α+270°)}/{sin(-180°-α)tan(α-270°)}的值
已知α是第二象限角,tan(α-270°)=1/5 (1)求sinα和cosα的值已知α是第二象限角,tan(α-270°)=1/5(1)求sinα和cosα的值(2)求{sin(180°-α)cos(360°-α)tan(-α+270°)}/{sin(-180°-α)tan(α-270°)}的
已知α是第二象限角,tan(α-270°)=1/5
(1)求sinα和cosα的值
tan(α-270°)=-cota=1/5
cota=-1/5
tana=-5
tana=sina/cosa=-5 sina=-5cosa
sin^2a+cos^2a=1 26cos^2a=1 cosa=-√26/26 sina=√650/26
(2){sin(180°-α)cos(360°-α)tan(-α+270°)}/{sin(-180°-α)tan(α-270°)}
=(sina*cosa*cota)/(sina*(-cota))
=-cosa
=√26/26