[(1-log6(3))^2 + log6(2) × log6(18)]÷log6(4)最好有思考过程然后可以的话写解题过程=[log6(2)^2 + log6(2) × (log6(3)+1)]÷2log6(2) =(log6(2)+log6(3)+1)/2 这一步没看懂诶懂了.就是把log6(2)提出来约掉
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![[(1-log6(3))^2 + log6(2) × log6(18)]÷log6(4)最好有思考过程然后可以的话写解题过程=[log6(2)^2 + log6(2) × (log6(3)+1)]÷2log6(2) =(log6(2)+log6(3)+1)/2 这一步没看懂诶懂了.就是把log6(2)提出来约掉](/uploads/image/z/2701627-43-7.jpg?t=%5B%281-log6%283%29%29%5E2+%2B+log6%282%29+%C3%97+log6%2818%29%5D%C3%B7log6%284%29%E6%9C%80%E5%A5%BD%E6%9C%89%E6%80%9D%E8%80%83%E8%BF%87%E7%A8%8B%E7%84%B6%E5%90%8E%E5%8F%AF%E4%BB%A5%E7%9A%84%E8%AF%9D%E5%86%99%E8%A7%A3%E9%A2%98%E8%BF%87%E7%A8%8B%3D%5Blog6%282%29%5E2+%2B+log6%282%29+%C3%97+%28log6%283%29%2B1%29%5D%C3%B72log6%282%29+%3D%28log6%282%29%2Blog6%283%29%2B1%29%2F2+%E8%BF%99%E4%B8%80%E6%AD%A5%E6%B2%A1%E7%9C%8B%E6%87%82%E8%AF%B6%E6%87%82%E4%BA%86.%E5%B0%B1%E6%98%AF%E6%8A%8Alog6%282%29%E6%8F%90%E5%87%BA%E6%9D%A5%E7%BA%A6%E6%8E%89)
[(1-log6(3))^2 + log6(2) × log6(18)]÷log6(4)最好有思考过程然后可以的话写解题过程=[log6(2)^2 + log6(2) × (log6(3)+1)]÷2log6(2) =(log6(2)+log6(3)+1)/2 这一步没看懂诶懂了.就是把log6(2)提出来约掉
[(1-log6(3))^2 + log6(2) × log6(18)]÷log6(4)
最好有思考过程
然后可以的话写解题过程
=[log6(2)^2 + log6(2) × (log6(3)+1)]÷2log6(2)
=(log6(2)+log6(3)+1)/2
这一步没看懂诶
懂了.
就是把log6(2)提出来约掉
[(1-log6(3))^2 + log6(2) × log6(18)]÷log6(4)最好有思考过程然后可以的话写解题过程=[log6(2)^2 + log6(2) × (log6(3)+1)]÷2log6(2) =(log6(2)+log6(3)+1)/2 这一步没看懂诶懂了.就是把log6(2)提出来约掉
[(1-log6(3))^2 + log6(2) × log6(18)]÷log6(4)
=[log6(2)^2 + log6(2) × (log6(3)+1)]÷2log6(2)
=(log6(2)+log6(3)+1)/2
=(1+1)/2
=1
补充:
1-log6(3)=log6(6)-log6(3)=log6(2)
log6(18)=log6(3)+log6(6)=log6(3)+1
log6(4)=2*log6(2)
2^log4(2-根号3)^2+3^log(2+根号3)^2[(1-log6(3)^2+log6(2)*log6(18)]/log6(4)[(1-log6(3))^2+log6(2)*log6(18)]/log6(4)
[(1-log6 3)^2+log6 2-log6 18]/log6 4
求值:(log6 2)²+log6 3*log 6 2+log6 3,应该怎么算?
log6^3×log6^12+(log6^2)^2是log不是lg.........
{(1-log6 3)^2+log6 2*log6 18}/log6 4 等于多少,请写出就算过程,
((1-log6(3))²+log6(2)*log6(18))/log6(4)
[(1-log6 3)²+log6 2×log6 18]/log6 4
(log6 2)^2+log6 3*log6 12
(log6^2)^2+(log6^3)*(log6^4)+(log6^3)^2
(log6 3)^2+log6 2+log6 2log6 3=?
[(1-log6底3)^2+log6底2*log6底18]÷log6底4=
1.log6(1/12)-2log6(3)+1/3log6(27)=
化简1/2log6^12–2log6^√2 结果为log6^√3
化简1/2log6^12–2log6^√2 结果为log6^√3 快..
化简[(1-log6^3)^2+logb^2×log6^18]÷log6^4如题
[(1-log6(3))^2 + log6(2) × log6(18)]÷log6(4)最好有思考过程然后可以的话写解题过程=[log6(2)^2 + log6(2) × (log6(3)+1)]÷2log6(2) =(log6(2)+log6(3)+1)/2 这一步没看懂诶懂了.就是把log6(2)提出来约掉
(log6^4)(log6^18)+2(log6^3)^2
(log6 3)^2+log6 18乘以log6 2急求!!!!!!!!!!!!!!