设f(x)=【2sin^3θ+sin^2(2π-θ)+sin(π/2+θ)-3】/【2+2sin^2(π/2+θ)-sin(3π/2-θ)】,求f(π/3)的值快啊,坐等,急!要步骤的.
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![设f(x)=【2sin^3θ+sin^2(2π-θ)+sin(π/2+θ)-3】/【2+2sin^2(π/2+θ)-sin(3π/2-θ)】,求f(π/3)的值快啊,坐等,急!要步骤的.](/uploads/image/z/2666578-58-8.jpg?t=%E8%AE%BEf%28x%29%3D%E3%80%902sin%5E3%CE%B8%2Bsin%5E2%282%CF%80-%CE%B8%29%2Bsin%28%CF%80%2F2%2B%CE%B8%29-3%E3%80%91%2F%E3%80%902%2B2sin%5E2%28%CF%80%2F2%2B%CE%B8%29-sin%283%CF%80%2F2-%CE%B8%29%E3%80%91%2C%E6%B1%82f%28%CF%80%2F3%29%E7%9A%84%E5%80%BC%E5%BF%AB%E5%95%8A%2C%E5%9D%90%E7%AD%89%2C%E6%80%A5%21%E8%A6%81%E6%AD%A5%E9%AA%A4%E7%9A%84.)
设f(x)=【2sin^3θ+sin^2(2π-θ)+sin(π/2+θ)-3】/【2+2sin^2(π/2+θ)-sin(3π/2-θ)】,求f(π/3)的值快啊,坐等,急!要步骤的.
设f(x)=【2sin^3θ+sin^2(2π-θ)+sin(π/2+θ)-3】/【2+2sin^2(π/2+θ)-sin(3π/2-θ)】,求f(π/3)的值
快啊,坐等,急!要步骤的.
设f(x)=【2sin^3θ+sin^2(2π-θ)+sin(π/2+θ)-3】/【2+2sin^2(π/2+θ)-sin(3π/2-θ)】,求f(π/3)的值快啊,坐等,急!要步骤的.
sin(π/2+θ)=sinπ/2cosθ+cosπ/2sinθ=cosθ
sin(3π/2-θ)=cos(π-θ)=-cosθ
sinπ/3=√3/2 sin²π/3=3/4 sin³π/3=3√3/8
cosπ/3=1/2 cos²π/3=1/4
f(θ)
=[2sin³θ+sin²(2π-θ)+sin(π/2+θ)-3]/[2+2sin²(π/2+θ)-sin(3π/2-θ)]
=[2sin³θ+sin²θ+cosθ-3]/[2+2cos²θ+cosθ]
f(π/3)
=[2*(3√3/8)+3/4+1/2-3]/[2+2*(1/4)+1/2]
=(3√3/4-7/4)/3
=√3/4-7/12
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