高一数学幂函数比较大小问题将下列各组数用小于号从小到大排列:⑴2.5^(2/3),(-1.4)^(2/3),(-3)^(2/3)⑵0.16^(-3/4),0.5^(-3/2),6.25^(3/8)⑶(2/3)^(-1/3),(2/5)^(1/2),(5/3)^(-1/3),3^(1/3),(3/2)^(2/3)计算器我也会按、可
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![高一数学幂函数比较大小问题将下列各组数用小于号从小到大排列:⑴2.5^(2/3),(-1.4)^(2/3),(-3)^(2/3)⑵0.16^(-3/4),0.5^(-3/2),6.25^(3/8)⑶(2/3)^(-1/3),(2/5)^(1/2),(5/3)^(-1/3),3^(1/3),(3/2)^(2/3)计算器我也会按、可](/uploads/image/z/1781094-30-4.jpg?t=%E9%AB%98%E4%B8%80%E6%95%B0%E5%AD%A6%E5%B9%82%E5%87%BD%E6%95%B0%E6%AF%94%E8%BE%83%E5%A4%A7%E5%B0%8F%E9%97%AE%E9%A2%98%E5%B0%86%E4%B8%8B%E5%88%97%E5%90%84%E7%BB%84%E6%95%B0%E7%94%A8%E5%B0%8F%E4%BA%8E%E5%8F%B7%E4%BB%8E%E5%B0%8F%E5%88%B0%E5%A4%A7%E6%8E%92%E5%88%97%EF%BC%9A%E2%91%B42.5%5E%282%2F3%29%2C%28-1.4%29%5E%282%2F3%29%2C%28-3%29%5E%282%2F3%29%E2%91%B50.16%5E%28-3%2F4%29%2C0.5%5E%28-3%2F2%29%2C6.25%5E%283%2F8%29%E2%91%B6%282%2F3%29%5E%28-1%2F3%29%2C%282%2F5%29%5E%281%2F2%29%2C%285%2F3%29%5E%28-1%2F3%29%2C3%5E%281%2F3%29%2C%283%2F2%29%5E%282%2F3%29%E8%AE%A1%E7%AE%97%E5%99%A8%E6%88%91%E4%B9%9F%E4%BC%9A%E6%8C%89%E3%80%81%E5%8F%AF)
高一数学幂函数比较大小问题将下列各组数用小于号从小到大排列:⑴2.5^(2/3),(-1.4)^(2/3),(-3)^(2/3)⑵0.16^(-3/4),0.5^(-3/2),6.25^(3/8)⑶(2/3)^(-1/3),(2/5)^(1/2),(5/3)^(-1/3),3^(1/3),(3/2)^(2/3)计算器我也会按、可
高一数学幂函数比较大小问题
将下列各组数用小于号从小到大排列:
⑴2.5^(2/3),(-1.4)^(2/3),(-3)^(2/3)
⑵0.16^(-3/4),0.5^(-3/2),6.25^(3/8)
⑶(2/3)^(-1/3),(2/5)^(1/2),(5/3)^(-1/3),3^(1/3),(3/2)^(2/3)
计算器我也会按、可是我要具体过程= =、拜托各位了
根据回答质量给悬赏、= =
在线等呃、有没有会旳人?
急要呃
http://zhidao.baidu.com/question/122262612.html这是如果你看不懂我打的啥可以参考此图、
高一数学幂函数比较大小问题将下列各组数用小于号从小到大排列:⑴2.5^(2/3),(-1.4)^(2/3),(-3)^(2/3)⑵0.16^(-3/4),0.5^(-3/2),6.25^(3/8)⑶(2/3)^(-1/3),(2/5)^(1/2),(5/3)^(-1/3),3^(1/3),(3/2)^(2/3)计算器我也会按、可
楼上的没看清楚,底数虽然为负数,但是指数的分子部分是偶数,故可以化为正数
(1)(-1.4)^(2/3)=(1.4)^(2/3)
(-3)^(2/3)=3^(2/3)
指数相等,底数大的值比较大
则(-1.4)^(2/3)<2.5^(2/3)<(-3)^(2/3)
(2)0.16^(-3/4)=(5/2)^(3/2)
0.5^(-3/2)=2^(3/2)
6.25^(3/8)=(5/2)^(3/4)
∵(5/2)^(3/2)>(5/2)^(3/4)
(5/2)^(3/2)>2^(3/2)
(5/2)^(3/4)=(√10/2)^(3/2)
(√10/2)^(3/2)>2^(3/2)
∴0.5^(-3/2)<6.25^(3/8)<0.16^(-3/4)
(3)(2/3)^(-1/3)=(3/2)^(1/3)
(2/5)^(1/2)=(2√10/25)^(1/3)
(5/3)^(-1/3)=(3/5)^(1/3)
3^(1/3)=3^(1/3)
(3/2)^(2/3)=(9/4)^(1/3)
(2√10/25)^(1/3)<(3/5)^(1/3)<(3/2)^(1/3)<(9/4)^(1/3)<3^(1/3)
∴(2/5)^(1/2)<(5/3)^(-1/3)<(2/3)^(-1/3)<(3/2)^(2/3)<3^(1/3)
幂函数的底不能少于0,所以有几个式子是不对的
可采用中间值法。。。