设函数f(x)在〔0,1〕上连续,在(0,1)内可导,且f(0)=f(1)=0,f(1/2)=1设函数f(x)在(0,1]上连续,在(0,1)内可导,且f(0)=f(1)=0,f(1/2)=1,证明:必存在ζ∈(0,1),使F‘(ζ)=1
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![设函数f(x)在〔0,1〕上连续,在(0,1)内可导,且f(0)=f(1)=0,f(1/2)=1设函数f(x)在(0,1]上连续,在(0,1)内可导,且f(0)=f(1)=0,f(1/2)=1,证明:必存在ζ∈(0,1),使F‘(ζ)=1](/uploads/image/z/15132890-2-0.jpg?t=%E8%AE%BE%E5%87%BD%E6%95%B0f%28x%29%E5%9C%A8%E3%80%940%2C1%E3%80%95%E4%B8%8A%E8%BF%9E%E7%BB%AD%2C%E5%9C%A8%280%2C1%29%E5%86%85%E5%8F%AF%E5%AF%BC%2C%E4%B8%94f%280%29%3Df%281%29%3D0%2Cf%281%2F2%29%3D1%E8%AE%BE%E5%87%BD%E6%95%B0f%28x%29%E5%9C%A8%280%2C1%5D%E4%B8%8A%E8%BF%9E%E7%BB%AD%2C%E5%9C%A8%280%2C1%29%E5%86%85%E5%8F%AF%E5%AF%BC%2C%E4%B8%94f%280%29%3Df%281%29%3D0%2Cf%281%2F2%29%3D1%2C%E8%AF%81%E6%98%8E%3A%E5%BF%85%E5%AD%98%E5%9C%A8%CE%B6%E2%88%88%280%2C1%29%2C%E4%BD%BFF%E2%80%98%28%CE%B6%29%3D1)
设函数f(x)在〔0,1〕上连续,在(0,1)内可导,且f(0)=f(1)=0,f(1/2)=1设函数f(x)在(0,1]上连续,在(0,1)内可导,且f(0)=f(1)=0,f(1/2)=1,证明:必存在ζ∈(0,1),使F‘(ζ)=1
设函数f(x)在〔0,1〕上连续,在(0,1)内可导,且f(0)=f(1)=0,f(1/2)=1
设函数f(x)在(0,1]上连续,在(0,1)内可导,且f(0)=f(1)=0,f(1/2)=1,证明:必存在ζ∈(0,1),使F‘(ζ)=1
设函数f(x)在〔0,1〕上连续,在(0,1)内可导,且f(0)=f(1)=0,f(1/2)=1设函数f(x)在(0,1]上连续,在(0,1)内可导,且f(0)=f(1)=0,f(1/2)=1,证明:必存在ζ∈(0,1),使F‘(ζ)=1
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设函数f(x)在〔0,1〕上连续,在(0,1)内可导,且f(0)=f(1)=0,f(1/2)=1设函数f(x)在(0,1]上连续,在(0,1)内可导,且f(0)=f(1)=0,f(1/2)=1,证明:必存在ζ∈(0,1),使F‘(ζ)=1
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