Observe that 18 = 42 + 12 + 12 + 02.How many of the first fifteen positive integers can be written as the sum of the squares of four integers 马上要考试啦T 后面 的四个数分别是是4的二次方,1的二次方,1的二次方,0的二次方,
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![Observe that 18 = 42 + 12 + 12 + 02.How many of the first fifteen positive integers can be written as the sum of the squares of four integers 马上要考试啦T 后面 的四个数分别是是4的二次方,1的二次方,1的二次方,0的二次方,](/uploads/image/z/1343125-37-5.jpg?t=Observe+that+18+%3D+42+%2B+12+%2B+12+%2B+02.How+many+of+the+first+fifteen+positive+integers+can+be+written+as+the+sum+of+the+squares+of+four+integers+%E9%A9%AC%E4%B8%8A%E8%A6%81%E8%80%83%E8%AF%95%E5%95%A6T+%E5%90%8E%E9%9D%A2+%E7%9A%84%E5%9B%9B%E4%B8%AA%E6%95%B0%E5%88%86%E5%88%AB%E6%98%AF%E6%98%AF4%E7%9A%84%E4%BA%8C%E6%AC%A1%E6%96%B9%2C1%E7%9A%84%E4%BA%8C%E6%AC%A1%E6%96%B9%2C1%E7%9A%84%E4%BA%8C%E6%AC%A1%E6%96%B9%2C0%E7%9A%84%E4%BA%8C%E6%AC%A1%E6%96%B9%2C)
Observe that 18 = 42 + 12 + 12 + 02.How many of the first fifteen positive integers can be written as the sum of the squares of four integers 马上要考试啦T 后面 的四个数分别是是4的二次方,1的二次方,1的二次方,0的二次方,
Observe that 18 = 42 + 12 + 12 + 02.How many of the first fifteen positive integers can be written as the sum of the squares of four integers
马上要考试啦T 后面 的四个数分别是是4的二次方,1的二次方,1的二次方,0的二次方,别看错了.
Observe that 18 = 42 + 12 + 12 + 02.How many of the first fifteen positive integers can be written as the sum of the squares of four integers 马上要考试啦T 后面 的四个数分别是是4的二次方,1的二次方,1的二次方,0的二次方,
观察18=42+12+12+02.请问前十五正整数,有多少个数字可以写成4个整数的平方之和呢?
1=12+02+02+02
2=12+12+02+02
3=12+12+12+02
4=12+12+12+12或4=22+02+02+02
5=22+12+02+02
..
..
..
13=32+22+02+02
14=32+22+12+02
15=32+22+12+12
由观察可知,4个整数可以重复,还包括0,这样一来,前15个正整数都是可以写成题目所给出的形式的.综上,答案就是15了.
请参考采纳.