cos25πtdt (0~π/4)的微积分怎么求?f(0~π/4)cos25πtdt麻烦过程详细一点,这里的dt什么意思?原函数是(sin25πt)/25π吗?谢谢~!
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![cos25πtdt (0~π/4)的微积分怎么求?f(0~π/4)cos25πtdt麻烦过程详细一点,这里的dt什么意思?原函数是(sin25πt)/25π吗?谢谢~!](/uploads/image/z/13403928-48-8.jpg?t=cos25%CF%80tdt+%EF%BC%880%7E%CF%80%2F4%EF%BC%89%E7%9A%84%E5%BE%AE%E7%A7%AF%E5%88%86%E6%80%8E%E4%B9%88%E6%B1%82%3Ff%EF%BC%880%7E%CF%80%2F4%EF%BC%89cos25%CF%80tdt%E9%BA%BB%E7%83%A6%E8%BF%87%E7%A8%8B%E8%AF%A6%E7%BB%86%E4%B8%80%E7%82%B9%2C%E8%BF%99%E9%87%8C%E7%9A%84dt%E4%BB%80%E4%B9%88%E6%84%8F%E6%80%9D%3F%E5%8E%9F%E5%87%BD%E6%95%B0%E6%98%AF%EF%BC%88sin25%CF%80t%EF%BC%89%2F25%CF%80%E5%90%97%3F%E8%B0%A2%E8%B0%A2%7E%21)
cos25πtdt (0~π/4)的微积分怎么求?f(0~π/4)cos25πtdt麻烦过程详细一点,这里的dt什么意思?原函数是(sin25πt)/25π吗?谢谢~!
cos25πtdt (0~π/4)的微积分怎么求?
f(0~π/4)cos25πtdt
麻烦过程详细一点,这里的dt什么意思?原函数是(sin25πt)/25π吗?
谢谢~!
cos25πtdt (0~π/4)的微积分怎么求?f(0~π/4)cos25πtdt麻烦过程详细一点,这里的dt什么意思?原函数是(sin25πt)/25π吗?谢谢~!
∫(0~π/4)cos25πtdt
=1/(25π)∫(0~π/4)cos25πtd25πt
=1/(25π)sin25πt (0~π/4)
=1/(25π)[sin(25π*π/4)-sin0]
=sin(25π²/4)/(25π)
答:
(0→π/4) ∫ cos(25πt) dt
=(0→π/4) (1/25π)* ∫cos(25πt) d(25πt)
=(0→π/4) sin(25πt) /(25π)
=sin(25π²/4) /(25π)
dt是微元、微分,cos(25πt)的原函数是sin(25πt)/(25π)
cos25πtdt (0~π/4)的微积分怎么求?f(0~π/4)cos25πtdt麻烦过程详细一点,这里的dt什么意思?原函数是(sin25πt)/25π吗?谢谢~!
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