用双线性法则设计的低通滤波器为什么不能滤掉高频信号?用matlab设计的,原型是butterworth滤波器,程序如下clcclear allb=[0.2932,0.5865,0.2932]a=[1,0,0.1716]t=0:0.1:10;x=sin(0.5*pi*t)+sin(2*pi*t);x1=sin(0.5*pi*t)x2=sin(2
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![用双线性法则设计的低通滤波器为什么不能滤掉高频信号?用matlab设计的,原型是butterworth滤波器,程序如下clcclear allb=[0.2932,0.5865,0.2932]a=[1,0,0.1716]t=0:0.1:10;x=sin(0.5*pi*t)+sin(2*pi*t);x1=sin(0.5*pi*t)x2=sin(2](/uploads/image/z/12142899-27-9.jpg?t=%E7%94%A8%E5%8F%8C%E7%BA%BF%E6%80%A7%E6%B3%95%E5%88%99%E8%AE%BE%E8%AE%A1%E7%9A%84%E4%BD%8E%E9%80%9A%E6%BB%A4%E6%B3%A2%E5%99%A8%E4%B8%BA%E4%BB%80%E4%B9%88%E4%B8%8D%E8%83%BD%E6%BB%A4%E6%8E%89%E9%AB%98%E9%A2%91%E4%BF%A1%E5%8F%B7%3F%E7%94%A8matlab%E8%AE%BE%E8%AE%A1%E7%9A%84%2C%E5%8E%9F%E5%9E%8B%E6%98%AFbutterworth%E6%BB%A4%E6%B3%A2%E5%99%A8%2C%E7%A8%8B%E5%BA%8F%E5%A6%82%E4%B8%8Bclcclear+allb%3D%5B0.2932%2C0.5865%2C0.2932%5Da%3D%5B1%2C0%2C0.1716%5Dt%3D0%3A0.1%3A10%3Bx%3Dsin%280.5%2Api%2At%29%2Bsin%282%2Api%2At%29%3Bx1%3Dsin%280.5%2Api%2At%29x2%3Dsin%282)
用双线性法则设计的低通滤波器为什么不能滤掉高频信号?用matlab设计的,原型是butterworth滤波器,程序如下clcclear allb=[0.2932,0.5865,0.2932]a=[1,0,0.1716]t=0:0.1:10;x=sin(0.5*pi*t)+sin(2*pi*t);x1=sin(0.5*pi*t)x2=sin(2
用双线性法则设计的低通滤波器为什么不能滤掉高频信号?
用matlab设计的,原型是butterworth滤波器,程序如下
clcclear all
b=[0.2932,0.5865,0.2932]a=[1,0,0.1716]
t=0:0.1:10;
x=sin(0.5*pi*t)+sin(2*pi*t);
x1=sin(0.5*pi*t)
x2=sin(2*pi*t)
y=filter(b,a,x);
figure(1)
plot(t,y)
figure(2)
plot(t,x)
但是每次运行后两张图形完全一样,高频信号没有被滤掉,不知道是为什么,
用双线性法则设计的低通滤波器为什么不能滤掉高频信号?用matlab设计的,原型是butterworth滤波器,程序如下clcclear allb=[0.2932,0.5865,0.2932]a=[1,0,0.1716]t=0:0.1:10;x=sin(0.5*pi*t)+sin(2*pi*t);x1=sin(0.5*pi*t)x2=sin(2
首先,那贴的程序有些问题,该加的标点符号没有加.这里就不说了.
其次你的所谓高频低频信号其实频率相差不算大(实践里的真正差别是数量级差别的!)简单滤波器是看不出效果的.而且你的滤波器特性就那么一般般,更看不出效果了.建议你用freqs(a,b)或者freqs(a,b,w)看看你的滤波器频率特性,那就明白了.