应用题 (16 18:57:14)直线AB与CD相交于点O,∠AOC:∠AOD=2:3.求∠BOD的度数.
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![应用题 (16 18:57:14)直线AB与CD相交于点O,∠AOC:∠AOD=2:3.求∠BOD的度数.](/uploads/image/z/1164809-65-9.jpg?t=%E5%BA%94%E7%94%A8%E9%A2%98+%2816+18%3A57%3A14%29%E7%9B%B4%E7%BA%BFAB%E4%B8%8ECD%E7%9B%B8%E4%BA%A4%E4%BA%8E%E7%82%B9O%2C%E2%88%A0AOC%EF%BC%9A%E2%88%A0AOD%3D2%3A3.%E6%B1%82%E2%88%A0BOD%E7%9A%84%E5%BA%A6%E6%95%B0.)
应用题 (16 18:57:14)直线AB与CD相交于点O,∠AOC:∠AOD=2:3.求∠BOD的度数.
应用题 (16 18:57:14)
直线AB与CD相交于点O,∠AOC:∠AOD=2:3.求∠BOD的度数.
应用题 (16 18:57:14)直线AB与CD相交于点O,∠AOC:∠AOD=2:3.求∠BOD的度数.
∠AOC:∠AOD=2:3
∠AOC=2/3∠AOD
∠AOC+∠AOD=180
2/3∠AOD+∠AOD=180
∠AOD=108
∠BOD=∠AOC=180-108=72度.