第一题:1/(x-1)+1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4) 第二题:若a
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/27 16:05:01
![第一题:1/(x-1)+1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4) 第二题:若a](/uploads/image/z/11523319-7-9.jpg?t=%E7%AC%AC%E4%B8%80%E9%A2%98%EF%BC%9A1%2F%EF%BC%88x-1%EF%BC%89%2B1%2F%28x-1%29%28x-2%29%2B1%2F%28x-2%29%28x-3%29%2B1%2F%28x-3%29%28x-4%29+%E7%AC%AC%E4%BA%8C%E9%A2%98%EF%BC%9A%E8%8B%A5a)
第一题:1/(x-1)+1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4) 第二题:若a
第一题:1/(x-1)+1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4)
第二题:若a
第一题:1/(x-1)+1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4) 第二题:若a
第一题是化简吧,如下:
1/(x-1)+ 1/(x-1)(x-2) + 1/(x-2)(x-3) + 1/(x-3)(x-4)
= 1/(x-1) * [1 + 1/(x-2)] + 1/(x-2)(x-3) + 1/(x-3)(x-4)
= 1/(x-1) * [(x-1)/(x-2)] + 1/(x-2)(x-3) + 1/(x-3)(x-4)
= 1/(x-2) + 1/(x-2)(x-3) + 1/(x-3)(x-4)
= 1/(x-2) * [1 + 1/(x-3)] + 1/(x-3)(x-4)
= 1/(x-2) * [(x-2)/(x-3)] + 1/(x-3)(x-4)
= 1/(x-3) + 1/(x-3)(x-4)
= 1/(x-3) * [1 + 1/(x-4)]
= 1/(x-3) * [(x-3)/(x-4)]
= 1/(x-4)
看到题别慌,一点一点来就行了.
第二题,说实在的,我是真没看懂:(
不过因为a
第一题 1/(x-1)(x-2)=1/(x-2)-1/(x-1)每个式子都能这么写
最后该抵消的都抵消了剩下1/(x-2)-1/(x-3)
a<-b<1 所以a+b<0 b+1>0 你自己化简吧 因为你用文字写的式子我可能搞不清楚
第一题:1/(x-1)+1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4)
=1/(x-1)+1/(x-2)-1/(x-1)+1/(x-3)-1/(x-2)+1/(x-4)-1/(x-3)
=1/(x-4)
第二题题目有问题,如果按照你的题目,答案就是0