几道数学题,要用因式分解的方法,先展开再分解,1.(2a-b)^2+8ab2.(a-b)^2+4ab3.(p-4)(p+1)+3p4.ab(c^2 - d^2)-(a^2 - b^2)cd5.2(x^2 -3ab)+x(4a-3b)6.a(a-b)^2-1+2b-b^27.x(x+z)-y(y+z)
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![几道数学题,要用因式分解的方法,先展开再分解,1.(2a-b)^2+8ab2.(a-b)^2+4ab3.(p-4)(p+1)+3p4.ab(c^2 - d^2)-(a^2 - b^2)cd5.2(x^2 -3ab)+x(4a-3b)6.a(a-b)^2-1+2b-b^27.x(x+z)-y(y+z)](/uploads/image/z/11496932-44-2.jpg?t=%E5%87%A0%E9%81%93%E6%95%B0%E5%AD%A6%E9%A2%98%2C%E8%A6%81%E7%94%A8%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%E7%9A%84%E6%96%B9%E6%B3%95%2C%E5%85%88%E5%B1%95%E5%BC%80%E5%86%8D%E5%88%86%E8%A7%A3%2C1.%EF%BC%882a-b%EF%BC%89%5E2%2B8ab2.%28a-b%29%5E2%2B4ab3.%28p-4%29%28p%2B1%29%2B3p4.ab%28c%5E2+-+d%5E2%29-%28a%5E2+-+b%5E2%29cd5.2%28x%5E2+-3ab%29%2Bx%284a-3b%296.a%28a-b%29%5E2-1%2B2b-b%5E27.x%28x%2Bz%29-y%28y%2Bz%29)
几道数学题,要用因式分解的方法,先展开再分解,1.(2a-b)^2+8ab2.(a-b)^2+4ab3.(p-4)(p+1)+3p4.ab(c^2 - d^2)-(a^2 - b^2)cd5.2(x^2 -3ab)+x(4a-3b)6.a(a-b)^2-1+2b-b^27.x(x+z)-y(y+z)
几道数学题,要用因式分解的方法,先展开再分解,
1.(2a-b)^2+8ab
2.(a-b)^2+4ab
3.(p-4)(p+1)+3p
4.ab(c^2 - d^2)-(a^2 - b^2)cd
5.2(x^2 -3ab)+x(4a-3b)
6.a(a-b)^2-1+2b-b^2
7.x(x+z)-y(y+z)
几道数学题,要用因式分解的方法,先展开再分解,1.(2a-b)^2+8ab2.(a-b)^2+4ab3.(p-4)(p+1)+3p4.ab(c^2 - d^2)-(a^2 - b^2)cd5.2(x^2 -3ab)+x(4a-3b)6.a(a-b)^2-1+2b-b^27.x(x+z)-y(y+z)
1.(2a-b)^2+8ab
=4a^2-4ab+b^2+8ab
=4a^2+4ab+b^2
=(2a+b)^2
2.(a-b)^2+4ab
=a^2-2ab+b^2+4ab
=a^2+2ab+b^2
=(a+b)^2
3.(p-4)(p+1)+3p
=p^2+p-4p-4+3p
=p^2+-4
=(p+2)(p-2)
4.ab(c^2 - d^2)-(a^2 - b^2)cd
=abc^2-abd^2-a^2cd+b^2cd
=abc^2+b^2cd-(abd^2+a^2cd)
=bc(ac+bd)-ad(bd+ac)
=(bc-ad)(ac+bd)
5.2(x^2 -3ab)+x(4a-3b)
=2x^2-6ab+4ax-3bx
=2x^2+x(4a-3b)-6ab
=(2x-3b)(x+2a)
6.若为(a-b)^2-1+2b-b^2
=(a-b)^2-(1-2b+b^2)
=(a-b)^2-(b^2-2b+1)
=(a-b)^2-(b-1)^2
=(a-b+b-1)(a-b-b+1)
=(a-1)(a-2b+1)
7.x(x+z)-y(y+z)
=x^2+xz-y^2-yz
=(x^2-y^2)+(xz-yz)
=(x+y)(x-y)+z(x-y)
=(x-y)(x+y+z)