用※代表一种运算,如果x※y=1/xy+1/(x+1)(y+A),且2※1=2/3,求2※(3※1).1+1/1+2+1/1+2+3······+1/1+2+3······+2009
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![用※代表一种运算,如果x※y=1/xy+1/(x+1)(y+A),且2※1=2/3,求2※(3※1).1+1/1+2+1/1+2+3······+1/1+2+3······+2009](/uploads/image/z/1120726-46-6.jpg?t=%E7%94%A8%E2%80%BB%E4%BB%A3%E8%A1%A8%E4%B8%80%E7%A7%8D%E8%BF%90%E7%AE%97%2C%E5%A6%82%E6%9E%9Cx%E2%80%BBy%3D1%2Fxy%EF%BC%8B1%2F%28x%EF%BC%8B1%29%28y%EF%BC%8BA%29%2C%E4%B8%942%E2%80%BB1%3D2%2F3%2C%E6%B1%822%E2%80%BB%EF%BC%883%E2%80%BB1%EF%BC%89.1%EF%BC%8B1%2F1%EF%BC%8B2%EF%BC%8B1%2F1%EF%BC%8B2%EF%BC%8B3%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%EF%BC%8B1%2F1%EF%BC%8B2%EF%BC%8B3%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%EF%BC%8B2009)
用※代表一种运算,如果x※y=1/xy+1/(x+1)(y+A),且2※1=2/3,求2※(3※1).1+1/1+2+1/1+2+3······+1/1+2+3······+2009
用※代表一种运算,如果x※y=1/xy+1/(x+1)(y+A),且2※1=2/3,求2※(3※1).
1+1/1+2+1/1+2+3······+1/1+2+3······+2009
用※代表一种运算,如果x※y=1/xy+1/(x+1)(y+A),且2※1=2/3,求2※(3※1).1+1/1+2+1/1+2+3······+1/1+2+3······+2009
因为2※1=2/3
而x※y=1/xy+1/(x+1)(y+A)
2※1=1/2+1/(3×1+3A)=2/3
1/2+1/(3×1+3A)=2/3
1/(3×1+3A)=2/3-1/2
1/(3×1+3A)=1/6
3+3A=6
A=1
那么3※1=1/3+1/(4×2)=1/3+1/6=1/2
2※1/2=1/1+1/(3×3/2)=1+2/9=11/9
因此2※(3※1)=11/9
2※1=1/2+1/(2+1)(1+A)=2/3
A=1
然后代入。。
2※1=1/2+1/(2+1)(1+A)=2/3,得A=1.
2※(3※1)=2※(1/3+1/8)=2※11/24=1/(11/12)+1/(35/8)=508/385
按照运算法则:x=2 , y=1
2※1=1/(2*1) + 1/( 2+1)( 1+A) = 2/3
解得:A=1.
x=3, y=1
(3※1)= 1/(3*1) +1/(3+1)(1+1)=11/24
2※(3※1)=2※(11/24) =508/385 ( 最后计算你再验证一下)
方法是上述讲的规则来计算就行。