matlab函数周期问题function T0=torque(p,H,x01,y01,z01,a,b,c,a1,b1,c1)global JT=0;t1=zeros(1,6);for n=1:6kz=H*sin(p);ky=H*cos(p); %力臂t1(n)=forcey(p,x01,y01,z01,a,b,c,a1,b1,c1,J)*ky+forcez(p,y01,z01,a,b,c,a1,b1,c1,J)*kz; %一对磁体产生的
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![matlab函数周期问题function T0=torque(p,H,x01,y01,z01,a,b,c,a1,b1,c1)global JT=0;t1=zeros(1,6);for n=1:6kz=H*sin(p);ky=H*cos(p); %力臂t1(n)=forcey(p,x01,y01,z01,a,b,c,a1,b1,c1,J)*ky+forcez(p,y01,z01,a,b,c,a1,b1,c1,J)*kz; %一对磁体产生的](/uploads/image/z/1074951-63-1.jpg?t=matlab%E5%87%BD%E6%95%B0%E5%91%A8%E6%9C%9F%E9%97%AE%E9%A2%98function+T0%3Dtorque%28p%2CH%2Cx01%2Cy01%2Cz01%2Ca%2Cb%2Cc%2Ca1%2Cb1%2Cc1%29global+JT%3D0%3Bt1%3Dzeros%281%2C6%29%3Bfor+n%3D1%3A6kz%3DH%2Asin%28p%29%3Bky%3DH%2Acos%28p%29%3B+%25%E5%8A%9B%E8%87%82t1%28n%29%3Dforcey%28p%2Cx01%2Cy01%2Cz01%2Ca%2Cb%2Cc%2Ca1%2Cb1%2Cc1%2CJ%29%2Aky%2Bforcez%28p%2Cy01%2Cz01%2Ca%2Cb%2Cc%2Ca1%2Cb1%2Cc1%2CJ%29%2Akz%3B+%25%E4%B8%80%E5%AF%B9%E7%A3%81%E4%BD%93%E4%BA%A7%E7%94%9F%E7%9A%84)
matlab函数周期问题function T0=torque(p,H,x01,y01,z01,a,b,c,a1,b1,c1)global JT=0;t1=zeros(1,6);for n=1:6kz=H*sin(p);ky=H*cos(p); %力臂t1(n)=forcey(p,x01,y01,z01,a,b,c,a1,b1,c1,J)*ky+forcez(p,y01,z01,a,b,c,a1,b1,c1,J)*kz; %一对磁体产生的
matlab函数周期问题
function T0=torque(p,H,x01,y01,z01,a,b,c,a1,b1,c1)
global J
T=0;
t1=zeros(1,6);
for n=1:6
kz=H*sin(p);
ky=H*cos(p); %力臂
t1(n)=forcey(p,x01,y01,z01,a,b,c,a1,b1,c1,J)*ky+forcez(p,y01,z01,a,b,c,a1,b1,c1,J)*kz; %一对磁体产生的扭矩
T=T+t1(n);
p=p+pi/3; %p为角度
end
T0=6*T; %三对磁极产生的总扭矩
forcey和forcez的周期是pi*2,torque函数的周期应该是pi/3,而运行后出来的图像却是pi*2.
matlab函数周期问题function T0=torque(p,H,x01,y01,z01,a,b,c,a1,b1,c1)global JT=0;t1=zeros(1,6);for n=1:6kz=H*sin(p);ky=H*cos(p); %力臂t1(n)=forcey(p,x01,y01,z01,a,b,c,a1,b1,c1,J)*ky+forcez(p,y01,z01,a,b,c,a1,b1,c1,J)*kz; %一对磁体产生的
既然torque函数的周期应该是pi/3,那么p的步长就不应该是pi/3,而应该小于pi/3.要使得曲线光滑,建议每个周期最少取4点,最好取8点以上甚至16点以上,所以p的步长最好取pi/24或pi/48甚至更多.
:“既然torque函数的周期应该是pi/3,那么p的步长就不应该是pi/3,而应该小于pi/3。”这只是单纯的数学问题,与你如何应用无关。