matlab 计算精度d1=[0.5 1/2/3^0.5];d2=[-0.5 1/2/3^0.5];d3= [0 -1/3^0.5];b1=[2*pi 2*pi/3^0.5];b2=[-2*pi 2*pi/3^0.5];k=1/3*(b1-b2);>> exp(i*dot(k,d1))+exp(i*dot(k,d2))+exp(i*dot(k,d3))ans =4.4409e-016为什么结果不是零啊.这个结果无限接
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/02 17:19:12
![matlab 计算精度d1=[0.5 1/2/3^0.5];d2=[-0.5 1/2/3^0.5];d3= [0 -1/3^0.5];b1=[2*pi 2*pi/3^0.5];b2=[-2*pi 2*pi/3^0.5];k=1/3*(b1-b2);>> exp(i*dot(k,d1))+exp(i*dot(k,d2))+exp(i*dot(k,d3))ans =4.4409e-016为什么结果不是零啊.这个结果无限接](/uploads/image/z/10323275-59-5.jpg?t=matlab+%E8%AE%A1%E7%AE%97%E7%B2%BE%E5%BA%A6d1%3D%5B0.5+1%2F2%2F3%5E0.5%5D%3Bd2%3D%5B-0.5+1%2F2%2F3%5E0.5%5D%3Bd3%3D+%5B0+-1%2F3%5E0.5%5D%3Bb1%3D%5B2%2Api+2%2Api%2F3%5E0.5%5D%3Bb2%3D%5B-2%2Api+2%2Api%2F3%5E0.5%5D%3Bk%3D1%2F3%2A%28b1-b2%29%3B%3E%3E+exp%28i%2Adot%28k%2Cd1%29%29%2Bexp%28i%2Adot%28k%2Cd2%29%29%2Bexp%28i%2Adot%28k%2Cd3%29%29ans+%3D4.4409e-016%E4%B8%BA%E4%BB%80%E4%B9%88%E7%BB%93%E6%9E%9C%E4%B8%8D%E6%98%AF%E9%9B%B6%E5%95%8A.%E8%BF%99%E4%B8%AA%E7%BB%93%E6%9E%9C%E6%97%A0%E9%99%90%E6%8E%A5)
matlab 计算精度d1=[0.5 1/2/3^0.5];d2=[-0.5 1/2/3^0.5];d3= [0 -1/3^0.5];b1=[2*pi 2*pi/3^0.5];b2=[-2*pi 2*pi/3^0.5];k=1/3*(b1-b2);>> exp(i*dot(k,d1))+exp(i*dot(k,d2))+exp(i*dot(k,d3))ans =4.4409e-016为什么结果不是零啊.这个结果无限接
matlab 计算精度
d1=[0.5 1/2/3^0.5];
d2=[-0.5 1/2/3^0.5];
d3= [0 -1/3^0.5];
b1=[2*pi 2*pi/3^0.5];
b2=[-2*pi 2*pi/3^0.5];
k=1/3*(b1-b2);
>> exp(i*dot(k,d1))+exp(i*dot(k,d2))+exp(i*dot(k,d3))
ans =
4.4409e-016
为什么结果不是零啊.这个结果无限接近于零,怎么让它在结果中显示0
matlab 计算精度d1=[0.5 1/2/3^0.5];d2=[-0.5 1/2/3^0.5];d3= [0 -1/3^0.5];b1=[2*pi 2*pi/3^0.5];b2=[-2*pi 2*pi/3^0.5];k=1/3*(b1-b2);>> exp(i*dot(k,d1))+exp(i*dot(k,d2))+exp(i*dot(k,d3))ans =4.4409e-016为什么结果不是零啊.这个结果无限接
你可以将结果保留若干位小数:比如
>> t=4.4409e-016
t =
4.4409e-016
>> tt=round(t*10000)/10000
tt =
0
>>
这样就是保留4位小数了