已知(4x-2y-1)^2+根号xy-2=0,求4x^2y-4x^2y^2-2xy^2的值
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![已知(4x-2y-1)^2+根号xy-2=0,求4x^2y-4x^2y^2-2xy^2的值](/uploads/image/z/996112-64-2.jpg?t=%E5%B7%B2%E7%9F%A5%EF%BC%884x-2y-1%29%5E2%2B%E6%A0%B9%E5%8F%B7xy-2%3D0%2C%E6%B1%824x%5E2y-4x%5E2y%5E2-2xy%5E2%E7%9A%84%E5%80%BC)
已知(4x-2y-1)^2+根号xy-2=0,求4x^2y-4x^2y^2-2xy^2的值
已知(4x-2y-1)^2+根号xy-2=0,求4x^2y-4x^2y^2-2xy^2的值
已知(4x-2y-1)^2+根号xy-2=0,求4x^2y-4x^2y^2-2xy^2的值
(4x-2y-1)^2+根号xy-2=0
4x-2y-1=0
xy-2=0
2x-y=1/2
xy=2
4x^2y-4x^2y^2-2xy^2
=2xy(2x-2xy-y)
=2*2(1/2-4)
=4*-7/2
=-14