已知x+2y=0,xy不=0,求分式(x^2+2xy-y^2)/(2x^2+xy+y^2)的值
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![已知x+2y=0,xy不=0,求分式(x^2+2xy-y^2)/(2x^2+xy+y^2)的值](/uploads/image/z/976238-62-8.jpg?t=%E5%B7%B2%E7%9F%A5x%2B2y%3D0%2Cxy%E4%B8%8D%3D0%2C%E6%B1%82%E5%88%86%E5%BC%8F%28x%5E2%2B2xy-y%5E2%29%2F%282x%5E2%2Bxy%2By%5E2%29%E7%9A%84%E5%80%BC)
已知x+2y=0,xy不=0,求分式(x^2+2xy-y^2)/(2x^2+xy+y^2)的值
已知x+2y=0,xy不=0,求分式(x^2+2xy-y^2)/(2x^2+xy+y^2)的值
已知x+2y=0,xy不=0,求分式(x^2+2xy-y^2)/(2x^2+xy+y^2)的值
x+2y=0,x=-2y
(x^2+2xy-y^2)/(2x^2+xy+y^2)=(4y^2-4y^2-y^2)/(8y^2-2y^2-y^2)=-y^2/5y^2=-1/5