以相交两圆C1:x²+y²+4x+1=0及C2 :x²+y²+2x+2y+1=0的公共弦为直径的圆的方程
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/27 20:17:07
![以相交两圆C1:x²+y²+4x+1=0及C2 :x²+y²+2x+2y+1=0的公共弦为直径的圆的方程](/uploads/image/z/971659-19-9.jpg?t=%E4%BB%A5%E7%9B%B8%E4%BA%A4%E4%B8%A4%E5%9C%86C1%3Ax%26%23178%3B%2By%26%23178%3B%2B4x%2B1%3D0%E5%8F%8AC2+%3Ax%26%23178%3B%2By%26%23178%3B%2B2x%2B2y%2B1%3D0%E7%9A%84%E5%85%AC%E5%85%B1%E5%BC%A6%E4%B8%BA%E7%9B%B4%E5%BE%84%E7%9A%84%E5%9C%86%E7%9A%84%E6%96%B9%E7%A8%8B)
以相交两圆C1:x²+y²+4x+1=0及C2 :x²+y²+2x+2y+1=0的公共弦为直径的圆的方程
以相交两圆C1:x²+y²+4x+1=0及C2 :x²+y²+2x+2y+1=0的公共弦为直径的圆的方程
以相交两圆C1:x²+y²+4x+1=0及C2 :x²+y²+2x+2y+1=0的公共弦为直径的圆的方程
(x+3/2)2+(y+1/2)2=1/2