1.若(a+b)^2=40,(a-b)^2=60,则a^2+b^2=( ) ab=( )1(2x+3y+1)(2x-3y+1)-(2x-3y-1) 2(x-2)^2(x+2)^2(x^2+4)^23(1+2)(1+2^2)(1+2^4)...(1+2^2012)4[2x^2-(x+y)(x-y)][(2-x)(x+2)+(-y-2)(2+y)]其中x.y满足代数式4x^2+9y^2
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/29 19:17:45
![1.若(a+b)^2=40,(a-b)^2=60,则a^2+b^2=( ) ab=( )1(2x+3y+1)(2x-3y+1)-(2x-3y-1) 2(x-2)^2(x+2)^2(x^2+4)^23(1+2)(1+2^2)(1+2^4)...(1+2^2012)4[2x^2-(x+y)(x-y)][(2-x)(x+2)+(-y-2)(2+y)]其中x.y满足代数式4x^2+9y^2](/uploads/image/z/9428917-13-7.jpg?t=1.%E8%8B%A5%EF%BC%88a%2Bb%29%5E2%3D40%2C%EF%BC%88a-b%29%5E2%3D60%2C%E5%88%99a%5E2%2Bb%5E2%3D%EF%BC%88+%EF%BC%89+ab%3D%EF%BC%88+%EF%BC%891%EF%BC%882x%2B3y%2B1%29%282x-3y%2B1%29-%282x-3y-1%29+2%EF%BC%88x-2%29%5E2%28x%2B2%29%5E2%EF%BC%88x%5E2%2B4%EF%BC%89%5E23%EF%BC%881%2B2%EF%BC%89%EF%BC%881%2B2%5E2%EF%BC%89%EF%BC%881%2B2%5E4%EF%BC%89...%EF%BC%881%2B2%5E2012%EF%BC%894%5B2x%5E2-%EF%BC%88x%2By%29%EF%BC%88x-y%29%5D%5B%282-x%29%28x%2B2%29%2B%28-y-2%29%282%2By%29%5D%E5%85%B6%E4%B8%ADx.y%E6%BB%A1%E8%B6%B3%E4%BB%A3%E6%95%B0%E5%BC%8F4x%5E2%2B9y%5E2)
1.若(a+b)^2=40,(a-b)^2=60,则a^2+b^2=( ) ab=( )1(2x+3y+1)(2x-3y+1)-(2x-3y-1) 2(x-2)^2(x+2)^2(x^2+4)^23(1+2)(1+2^2)(1+2^4)...(1+2^2012)4[2x^2-(x+y)(x-y)][(2-x)(x+2)+(-y-2)(2+y)]其中x.y满足代数式4x^2+9y^2
1.若(a+b)^2=40,(a-b)^2=60,则a^2+b^2=( ) ab=( )
1(2x+3y+1)(2x-3y+1)-(2x-3y-1)
2(x-2)^2(x+2)^2(x^2+4)^2
3(1+2)(1+2^2)(1+2^4)...(1+2^2012)
4[2x^2-(x+y)(x-y)][(2-x)(x+2)+(-y-2)(2+y)]其中x.y满足代数式4x^2+9y^2-4x+12y-1取最小值时的x,y的取值
1.若(a+b)^2=40,(a-b)^2=60,则a^2+b^2=( ) ab=( )1(2x+3y+1)(2x-3y+1)-(2x-3y-1) 2(x-2)^2(x+2)^2(x^2+4)^23(1+2)(1+2^2)(1+2^4)...(1+2^2012)4[2x^2-(x+y)(x-y)][(2-x)(x+2)+(-y-2)(2+y)]其中x.y满足代数式4x^2+9y^2
标题:50,-5
1:(2x-1/2)^2-(3y+1/2)^2
2:X^8-32X^4+256
3:这个题应该是出错了吧,题目最后应该是1+2^2048,这样的话正确结果应该是2^4096-1
4:x=0.5,y=-2/3,结果自己带进去算吧