已经函数y=1+loga(x+2) 求反函数 用下面这种实验式子回答>> syms x>> y=asin(x)/acos(x);>> diff(y)ans =1/(1-x^2)^(1/2)/acos(x)+asin(x)/acos(x)^2/(1-x^2)^(1/2)
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![已经函数y=1+loga(x+2) 求反函数 用下面这种实验式子回答>> syms x>> y=asin(x)/acos(x);>> diff(y)ans =1/(1-x^2)^(1/2)/acos(x)+asin(x)/acos(x)^2/(1-x^2)^(1/2)](/uploads/image/z/8622514-10-4.jpg?t=%E5%B7%B2%E7%BB%8F%E5%87%BD%E6%95%B0y%3D1%2Bloga%28x%2B2%29+%E6%B1%82%E5%8F%8D%E5%87%BD%E6%95%B0+%E7%94%A8%E4%B8%8B%E9%9D%A2%E8%BF%99%E7%A7%8D%E5%AE%9E%E9%AA%8C%E5%BC%8F%E5%AD%90%E5%9B%9E%E7%AD%94%3E%3E+syms+x%3E%3E+y%3Dasin%28x%29%2Facos%28x%29%3B%3E%3E+diff%28y%29ans+%3D1%2F%281-x%5E2%29%5E%281%2F2%29%2Facos%28x%29%2Basin%28x%29%2Facos%28x%29%5E2%2F%281-x%5E2%29%5E%281%2F2%29)
已经函数y=1+loga(x+2) 求反函数 用下面这种实验式子回答>> syms x>> y=asin(x)/acos(x);>> diff(y)ans =1/(1-x^2)^(1/2)/acos(x)+asin(x)/acos(x)^2/(1-x^2)^(1/2)
已经函数y=1+loga(x+2) 求反函数
用下面这种实验式子回答
>> syms x
>> y=asin(x)/acos(x);
>> diff(y)
ans =
1/(1-x^2)^(1/2)/acos(x)+asin(x)/acos(x)^2/(1-x^2)^(1/2)
已经函数y=1+loga(x+2) 求反函数 用下面这种实验式子回答>> syms x>> y=asin(x)/acos(x);>> diff(y)ans =1/(1-x^2)^(1/2)/acos(x)+asin(x)/acos(x)^2/(1-x^2)^(1/2)
原式化为:1,loga (x+2)=y-1;2,(y+1)=x+2;3,x=a~(y-1) -2;4,y=a~(x-1) -2 (a>0).
他的答案是这样
原式可化为loga (x+2)=y-1;>>ln(x+2)/lna=y-1 计算机中只有ln 所以用换底的方式
a^(y+1)=x+2; >>a^(y+1)=x+2;
x=a^(y-1) -2; >>x=a^(y-1) -2;
将x,y对调可得反函数为
y=a^(x-1) -2 (a>0)。
>> syms x;syms a;
>> y=1+log(x+2)/log(a);
>> finverse(y)
ans =
-(-exp(x*log(a))+2*a)/a