设a²+2a-1=0,b的4次方-2b²-1=0,且1-ab²≠0,则(ab²+b²-3a+1/a)的5次方为?
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![设a²+2a-1=0,b的4次方-2b²-1=0,且1-ab²≠0,则(ab²+b²-3a+1/a)的5次方为?](/uploads/image/z/763845-69-5.jpg?t=%E8%AE%BEa%26%23178%3B%2B2a-1%3D0%2Cb%E7%9A%844%E6%AC%A1%E6%96%B9-2b%26%23178%3B-1%3D0%2C%E4%B8%941-ab%26%23178%3B%E2%89%A00%2C%E5%88%99%EF%BC%88ab%26%23178%3B%2Bb%26%23178%3B-3a%2B1%2Fa%EF%BC%89%E7%9A%845%E6%AC%A1%E6%96%B9%E4%B8%BA%3F)
设a²+2a-1=0,b的4次方-2b²-1=0,且1-ab²≠0,则(ab²+b²-3a+1/a)的5次方为?
设a²+2a-1=0,b的4次方-2b²-1=0,且1-ab²≠0,则(ab²+b²-3a+1/a)的5次方为?
设a²+2a-1=0,b的4次方-2b²-1=0,且1-ab²≠0,则(ab²+b²-3a+1/a)的5次方为?