1 求函数f(x)=3/[2(sinx)^2+1]+8/[3(cosx)^2+2](x∈R)的最小值已知a,b,c∈(1,2)2求y=1/根号[(a-1)(2-b)]+1/根号[(b-1)(2-c)]+1/根号[(c-1)(2-a)]的最小值4设ai是正实数,i=1,2,3,且1/a1+1/a2+1/a3=1,(1)求证1/根号a1a2 +根
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![1 求函数f(x)=3/[2(sinx)^2+1]+8/[3(cosx)^2+2](x∈R)的最小值已知a,b,c∈(1,2)2求y=1/根号[(a-1)(2-b)]+1/根号[(b-1)(2-c)]+1/根号[(c-1)(2-a)]的最小值4设ai是正实数,i=1,2,3,且1/a1+1/a2+1/a3=1,(1)求证1/根号a1a2 +根](/uploads/image/z/7254043-43-3.jpg?t=1+%E6%B1%82%E5%87%BD%E6%95%B0f%28x%29%3D3%2F%5B2%28sinx%29%5E2%2B1%5D%2B8%2F%5B3%28cosx%29%5E2%2B2%5D%EF%BC%88x%E2%88%88R%EF%BC%89%E7%9A%84%E6%9C%80%E5%B0%8F%E5%80%BC%E5%B7%B2%E7%9F%A5a%2Cb%2Cc%E2%88%88%EF%BC%881%2C2%EF%BC%892%E6%B1%82y%3D1%2F%E6%A0%B9%E5%8F%B7%5B%28a-1%29%282-b%29%5D%2B1%2F%E6%A0%B9%E5%8F%B7%5B%28b-1%29%282-c%29%5D%2B1%2F%E6%A0%B9%E5%8F%B7%5B%28c-1%29%282-a%29%5D%E7%9A%84%E6%9C%80%E5%B0%8F%E5%80%BC4%E8%AE%BEai%E6%98%AF%E6%AD%A3%E5%AE%9E%E6%95%B0%2Ci%3D1%2C2%2C3%2C%E4%B8%941%2Fa1%2B1%2Fa2%2B1%2Fa3%3D1%2C%EF%BC%881%EF%BC%89%E6%B1%82%E8%AF%811%2F%E6%A0%B9%E5%8F%B7a1a2+%2B%E6%A0%B9)
1 求函数f(x)=3/[2(sinx)^2+1]+8/[3(cosx)^2+2](x∈R)的最小值已知a,b,c∈(1,2)2求y=1/根号[(a-1)(2-b)]+1/根号[(b-1)(2-c)]+1/根号[(c-1)(2-a)]的最小值4设ai是正实数,i=1,2,3,且1/a1+1/a2+1/a3=1,(1)求证1/根号a1a2 +根
1 求函数f(x)=3/[2(sinx)^2+1]+8/[3(cosx)^2+2](x∈R)的最小值
已知a,b,c∈(1,2)
2求y=1/根号[(a-1)(2-b)]+1/根号[(b-1)(2-c)]+1/根号[(c-1)(2-a)]的最小值
4设ai是正实数,i=1,2,3,且1/a1+1/a2+1/a3=1,
(1)求证1/根号a1a2 +根号3/根号a1a2≤1(我觉得这题可用柯西不等式,但我做不出来.)
(2)求证a1/(1+a1)+a2/(1+a2)+a3/(1+a3)≥9/4
4设a,b,c∈(0,﹢∞)
求证a^2/b≥2ma-(m^2)b
1 求函数f(x)=3/[2(sinx)^2+1]+8/[3(cosx)^2+2](x∈R)的最小值已知a,b,c∈(1,2)2求y=1/根号[(a-1)(2-b)]+1/根号[(b-1)(2-c)]+1/根号[(c-1)(2-a)]的最小值4设ai是正实数,i=1,2,3,且1/a1+1/a2+1/a3=1,(1)求证1/根号a1a2 +根
将两个分式分子分母同时乘以3和2使三角函数的系数都是6然后用柯西的变种 就是分式的那种答案是49/13
首先用三元算数几何均值不等式放缩右边是3(x^2y^2z^2)^(1/3),其中x=[(a-1)(2-a)]^(-1/2) y,z是b和c的 x根号里面配方得到x>=2所以答案是6
(1)好像有问题
(2)分子分母同时除以ai同样利用柯西的分式变种以及已知条件可证
4.题目有问题