若f(2x-1)=x²+1,①求f(x),②求f(0)要过程!用换元法!
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/30 23:07:29
![若f(2x-1)=x²+1,①求f(x),②求f(0)要过程!用换元法!](/uploads/image/z/7207004-20-4.jpg?t=%E8%8B%A5f%282x-1%29%3Dx%26%23178%3B%2B1%2C%E2%91%A0%E6%B1%82f%28x%29%2C%E2%91%A1%E6%B1%82f%EF%BC%880%EF%BC%89%E8%A6%81%E8%BF%87%E7%A8%8B%21%E7%94%A8%E6%8D%A2%E5%85%83%E6%B3%95%EF%BC%81)
若f(2x-1)=x²+1,①求f(x),②求f(0)要过程!用换元法!
若f(2x-1)=x²+1,①求f(x),②求f(0)要过程!
用换元法!
若f(2x-1)=x²+1,①求f(x),②求f(0)要过程!用换元法!
令2x-1=t,x=t+1/2,f(t)=(t+1/2)^2+1,则f(x)=(x+1/2)^2+1,f(0)=5/4