已知集合m={x|(x+2)(x-1)小于0},n={x|x+1小于0},则m交n=?
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![已知集合m={x|(x+2)(x-1)小于0},n={x|x+1小于0},则m交n=?](/uploads/image/z/7042609-1-9.jpg?t=%E5%B7%B2%E7%9F%A5%E9%9B%86%E5%90%88m%3D%7Bx%7C%28x%2B2%29%28x-1%29%E5%B0%8F%E4%BA%8E0%7D%2Cn%3D%7Bx%7Cx%2B1%E5%B0%8F%E4%BA%8E0%7D%2C%E5%88%99m%E4%BA%A4n%3D%3F)
已知集合m={x|(x+2)(x-1)小于0},n={x|x+1小于0},则m交n=?
已知集合m={x|(x+2)(x-1)小于0},n={x|x+1小于0},则m交n=?
已知集合m={x|(x+2)(x-1)小于0},n={x|x+1小于0},则m交n=?
(x+2)(x-1)
M
(x+2)(x-1)<0
-2
x+1<0
x<-1
所以M∩N={x|-2
m={x|(x+2)(x-1)<0},
即m={x|-2
n={x|x<-1}
m∩n={x|-2
集合m=(-2,1) 集合n=(负无穷,-1)
m交n=(-2,-1)
X<-2或-2
00000000000000000000000000000000000000000000000000000000000000000000000000000000000
集合m={x|(x+2)(x-1)小于0}={x| -2
x+1<0的解为 x<-1
故m交n={x|-2