这道题怎么做 1,1,2,3,3,9,(),27,5() 3,9,21,39(),()1,1,2,3,3,9,(),27,5() 3,9,21,39(),()
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/27 20:12:12
![这道题怎么做 1,1,2,3,3,9,(),27,5() 3,9,21,39(),()1,1,2,3,3,9,(),27,5() 3,9,21,39(),()](/uploads/image/z/7011407-47-7.jpg?t=%E8%BF%99%E9%81%93%E9%A2%98%E6%80%8E%E4%B9%88%E5%81%9A+1%2C1%2C2%2C3%2C3%2C9%2C%EF%BC%88%EF%BC%89%2C27%2C5%EF%BC%88%EF%BC%89+3%2C9%2C21%2C39%EF%BC%88%EF%BC%89%2C%EF%BC%88%EF%BC%891%2C1%2C2%2C3%2C3%2C9%EF%BC%8C%EF%BC%88%EF%BC%89%EF%BC%8C27%2C5%EF%BC%88%EF%BC%89+3%2C9%2C21%2C39%EF%BC%88%EF%BC%89%EF%BC%8C%EF%BC%88%EF%BC%89)
这道题怎么做 1,1,2,3,3,9,(),27,5() 3,9,21,39(),()1,1,2,3,3,9,(),27,5() 3,9,21,39(),()
这道题怎么做 1,1,2,3,3,9,(),27,5() 3,9,21,39(),()
1,1,2,3,3,9,(),27,5()
3,9,21,39(),()
这道题怎么做 1,1,2,3,3,9,(),27,5() 3,9,21,39(),()1,1,2,3,3,9,(),27,5() 3,9,21,39(),()
上面是分别从奇数、偶数项找规律,得出答案,4,81
下面那题都是3的倍数,除以三后得到1,3,7,13,而它们两两之差为2,4,6.所以如果你看懂的话,就可得出答案是63,93
1,1,2,3,3,9,(4),27,5(81)
奇数项为自然数列,偶数项为为等比数列
3,9,21,39(63),(93)
为变换的等差数列