用配方法解2道方程,(1)x²+3x-2=0 (2)x²=4根号3 x+1
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![用配方法解2道方程,(1)x²+3x-2=0 (2)x²=4根号3 x+1](/uploads/image/z/700351-7-1.jpg?t=%E7%94%A8%E9%85%8D%E6%96%B9%E6%B3%95%E8%A7%A32%E9%81%93%E6%96%B9%E7%A8%8B%2C%EF%BC%881%EF%BC%89x%26%23178%3B%2B3x-2%3D0+%EF%BC%882%EF%BC%89x%26%23178%3B%3D4%E6%A0%B9%E5%8F%B73+x%2B1)
用配方法解2道方程,(1)x²+3x-2=0 (2)x²=4根号3 x+1
用配方法解2道方程,(1)x²+3x-2=0 (2)x²=4根号3 x+1
用配方法解2道方程,(1)x²+3x-2=0 (2)x²=4根号3 x+1
(1)x²+3x-2=0
x²+2(1.5x)+1.5²-1.5²-2=0
(x+1.5)²=1.5²+2
(x+1.5)²=17/4
x+1.5=±√17/2
x=±√17/2-1.5
(2)x²=4根号3 x+1
x²-4根号3 x=1
x²-2(2根号3 x)+12-12=1
(x-2根号3)²=12+1
x-2根号3=±根号13
x=±根号13+2根号3
希望可以帮到你.