化简:tan(π-α)·sin²(α+π/2)·cos(2π-α)/cos³(-α-π)·tan(α-2π)
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/27 13:36:14
![化简:tan(π-α)·sin²(α+π/2)·cos(2π-α)/cos³(-α-π)·tan(α-2π)](/uploads/image/z/657586-10-6.jpg?t=%E5%8C%96%E7%AE%80%EF%BC%9Atan%EF%BC%88%CF%80-%CE%B1%EF%BC%89%C2%B7sin%26%23178%3B%28%CE%B1%2B%CF%80%2F2%EF%BC%89%C2%B7cos%282%CF%80-%CE%B1%EF%BC%89%2Fcos%26%23179%3B%EF%BC%88-%CE%B1-%CF%80%29%C2%B7tan%EF%BC%88%CE%B1-2%CF%80%EF%BC%89)
化简:tan(π-α)·sin²(α+π/2)·cos(2π-α)/cos³(-α-π)·tan(α-2π)
化简:tan(π-α)·sin²(α+π/2)·cos(2π-α)/cos³(-α-π)·tan(α-2π)
化简:tan(π-α)·sin²(α+π/2)·cos(2π-α)/cos³(-α-π)·tan(α-2π)
可以化简成:
tan(π-α)=-tana
sin²(α+π/2)=cos^2a
cos(2π-α)=cosa
cos³(-α-π)=-cos^3a
tan(α-2π)=tana
你写的有点乱分不清那些在分子上那些在分母上,刚才没仔细看,
你自己带进去还是在重写一次