若根号x+1 +(3x+y-1)^2=0 求三次根号4x+y^2的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/28 11:55:56
![若根号x+1 +(3x+y-1)^2=0 求三次根号4x+y^2的值](/uploads/image/z/646781-5-1.jpg?t=%E8%8B%A5%E6%A0%B9%E5%8F%B7x%2B1+%2B%283x%2By-1%29%5E2%3D0+%E6%B1%82%E4%B8%89%E6%AC%A1%E6%A0%B9%E5%8F%B74x%2By%5E2%E7%9A%84%E5%80%BC)
若根号x+1 +(3x+y-1)^2=0 求三次根号4x+y^2的值
若根号x+1 +(3x+y-1)^2=0 求三次根号4x+y^2的值
若根号x+1 +(3x+y-1)^2=0 求三次根号4x+y^2的值
根号和平方数都是大于等于0,和为0,则:
x+1=0
3x+y-1=0
解得:
x=-1
y=4
所以:
³√4x+y²
=³√-4+16
=³√12