已知(a+2)²+丨b-3丨=0 求 3a²b-(2a平方+a²-2b)
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![已知(a+2)²+丨b-3丨=0 求 3a²b-(2a平方+a²-2b)](/uploads/image/z/628266-66-6.jpg?t=%E5%B7%B2%E7%9F%A5%EF%BC%88a%2B2%EF%BC%89%26%23178%3B%2B%E4%B8%A8b-3%E4%B8%A8%3D0+%E6%B1%82+3a%26%23178%3Bb-%282a%E5%B9%B3%E6%96%B9%2Ba%26%23178%3B-2b%29)
已知(a+2)²+丨b-3丨=0 求 3a²b-(2a平方+a²-2b)
已知(a+2)²+丨b-3丨=0 求 3a²b-(2a平方+a²-2b)
已知(a+2)²+丨b-3丨=0 求 3a²b-(2a平方+a²-2b)
(a+2)²+丨b-3丨=0
则a+2=0,b-3=0
则a=-2,b=3
3a²b-(2a平方+a²-2b)
=3*4*3-(2*4+4-2*3)
=36-6
=30