已知298K时,有下列反应:C(s) + O2(g)=C O2(g) ;△r1HmΘ=-393.51kJ/mol CO(g) + O2(g)= C O2(g) ; △r3Hm已知298K时,有下列反应:C(s) + O2(g)=C O2(g) ;△r1HmΘ=-393.51kJ/mol\x09CO(g) + O2(g)= C O2(g) ; △r3HmΘ=-282.99 kJ/mol,求反
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![已知298K时,有下列反应:C(s) + O2(g)=C O2(g) ;△r1HmΘ=-393.51kJ/mol CO(g) + O2(g)= C O2(g) ; △r3Hm已知298K时,有下列反应:C(s) + O2(g)=C O2(g) ;△r1HmΘ=-393.51kJ/mol\x09CO(g) + O2(g)= C O2(g) ; △r3HmΘ=-282.99 kJ/mol,求反](/uploads/image/z/6240855-39-5.jpg?t=%E5%B7%B2%E7%9F%A5298K%E6%97%B6%2C%E6%9C%89%E4%B8%8B%E5%88%97%E5%8F%8D%E5%BA%94%EF%BC%9AC%28s%29+%2B+O2%28g%29%3DC+O2%28g%29+%3B%E2%96%B3r1Hm%CE%98%3D-393.51kJ%2Fmol+CO%28g%29+%2B+O2%28g%29%3D+C+O2%28g%29+%3B+%E2%96%B3r3Hm%E5%B7%B2%E7%9F%A5298K%E6%97%B6%EF%BC%8C%E6%9C%89%E4%B8%8B%E5%88%97%E5%8F%8D%E5%BA%94%EF%BC%9AC%28s%29+%2B+O2%28g%29%3DC+O2%28g%29+%3B%E2%96%B3r1Hm%CE%98%3D-393.51kJ%2Fmol%5Cx09CO%28g%29+%2B+O2%28g%29%3D+C+O2%28g%29+%3B+%E2%96%B3r3Hm%CE%98%3D-282.99+kJ%2Fmol%2C%E6%B1%82%E5%8F%8D)
已知298K时,有下列反应:C(s) + O2(g)=C O2(g) ;△r1HmΘ=-393.51kJ/mol CO(g) + O2(g)= C O2(g) ; △r3Hm已知298K时,有下列反应:C(s) + O2(g)=C O2(g) ;△r1HmΘ=-393.51kJ/mol\x09CO(g) + O2(g)= C O2(g) ; △r3HmΘ=-282.99 kJ/mol,求反
已知298K时,有下列反应:C(s) + O2(g)=C O2(g) ;△r1HmΘ=-393.51kJ/mol CO(g) + O2(g)= C O2(g) ; △r3Hm
已知298K时,有下列反应:C(s) + O2(g)=C O2(g) ;△r1HmΘ=-393.51kJ/mol
\x09CO(g) + O2(g)= C O2(g) ; △r3HmΘ=-282.99 kJ/mol,求反应C(s) + O2(g) = CO
\x09的△r2HmΘ
已知298K时,有下列反应:C(s) + O2(g)=C O2(g) ;△r1HmΘ=-393.51kJ/mol CO(g) + O2(g)= C O2(g) ; △r3Hm已知298K时,有下列反应:C(s) + O2(g)=C O2(g) ;△r1HmΘ=-393.51kJ/mol\x09CO(g) + O2(g)= C O2(g) ; △r3HmΘ=-282.99 kJ/mol,求反
本题可以用盖斯定律来求解
C(s) + O2(g)=C O2(g) ;△r1HmΘ=-393.51kJ/mol……①
CO(g) + 1/2O2(g)= C O2(g) ; △r3HmΘ=-282.99 kJ/mol……②
因为方程①-方程②为C(s) + 1/2O2(g) = CO
所以该反应的△r2HmΘ=-393.51+282.99 =-110.16kJ/mol