分段函数的奇偶性怎么求?x²+2(x>0)y={ 0(x=0)-x²-2(x<0)
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分段函数的奇偶性怎么求?x²+2(x>0)y={ 0(x=0)-x²-2(x<0)
分段函数的奇偶性怎么求?
x²+2(x>0)
y={ 0(x=0)
-x²-2(x<0)
分段函数的奇偶性怎么求?x²+2(x>0)y={ 0(x=0)-x²-2(x<0)
分段求哈
当X>0时 -X<0
F(X) =X²+2
F(-X) =-(X²+2)
所以F(X)=-F(-X)
当X=0时F(X)=-F(-X)=0
当X<0时
结论出来了