若数列{an}满足:a(n+1)=1/2an-3,a1=1,且liman存在,则liman=_____【括号内为下标】
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/30 03:16:37
![若数列{an}满足:a(n+1)=1/2an-3,a1=1,且liman存在,则liman=_____【括号内为下标】](/uploads/image/z/5931240-24-0.jpg?t=%E8%8B%A5%E6%95%B0%E5%88%97%7Ban%7D%E6%BB%A1%E8%B6%B3%EF%BC%9Aa%28n%2B1%29%3D1%2F2an-3%2Ca1%3D1%2C%E4%B8%94liman%E5%AD%98%E5%9C%A8%2C%E5%88%99liman%3D_____%E3%80%90%E6%8B%AC%E5%8F%B7%E5%86%85%E4%B8%BA%E4%B8%8B%E6%A0%87%E3%80%91)
若数列{an}满足:a(n+1)=1/2an-3,a1=1,且liman存在,则liman=_____【括号内为下标】
若数列{an}满足:a(n+1)=1/2an-3,a1=1,且liman存在,则liman=_____【括号内为下标】
若数列{an}满足:a(n+1)=1/2an-3,a1=1,且liman存在,则liman=_____【括号内为下标】
设极限为x,a(n+1)=1/2an-3两边取极限得:x=1/2x-3
x=-6
a(n+1) = (1/2)an - 3
2a(n+1) = an - 6
∵ an 的极限存在,当n→∞时, lima(n+1) = liman, 设liman = A
∴ lim[1/2an - 3] = liman = A = 1/2 A - 3
∴ A = - 6
数列{an}满足a1=2,a(n+1)=2an+n+2,求an
周期性数列问题i已知数列{an}满足a(n+1)=2an (0
若数列{An}满足A1=2,nA(n+1)-(n+1)An=2,则数列{An}的通项公式A后面的n都是下标
数列an满足a1=1,a(n+1)=an/[(2an)+1],求a2010
数列[An]满足a1=2,a(n+1)=3an-2 求an
若数列an满足a1=1,an+1=2^nan...若数列an满足a1=1,a(n+1)=2^n·an,则数列an的通项公式?
已知数列an满足an=2a(n-1)+2^n-1,a4=81,若数列{(an+p)/2}为等差数列,求p
求一道很简单的数列题数列{a}满足an=(n^2+n+1)/3求an+1
已知数列an满足:a1=1,an-a(n-1)=n n大于等于2 求an
已知数列an满足a1=2,an=a(n-1)+2n,(n≥2),求an
已知数列{an}满足a1=33,a(n+1)-an=2n,则an/n的最小值
已知数列{an}满足a1=33,a(n+1)-an=2n,求an/n的最小值
已知数列an满足a1=100,a(n+1)-an=2n,则(an)/n的最小值为
已知数列{an}满足a1=1,a(n+1)=2an+1(n∈N)(1)求数列{an}的通项公式(2)若数列{bn}满足4^(b1-1).4^(b2-1)已知数列{an}满足a1=1,a(n+1)=2an+1(n∈N*)(1)求数列{an}的通项公式(2)若数列{bn}满足4^(b1-1).4^(b2-1).4^(b3-
已知数列{an}满足a1=2,a(n+1)-an=a(n+1)*an,则a31=?
数列{An}满足A1=1,A(n+3)=An+3,A(n+2)=An +2
数列{an},定义数列满足:Δan=a(n+1)-an,定义数列{(Δan)的平方}满足:(Δan)的平方=Δa(n+1)-Δan,若数列{2^Δan}中各项均为1,且a21=a2012=0,则a1=?若数列{(Δan)的平方}中各项均为1 不好意思,
已知数列{a}满足a1=1/2,a(n+1)=an+1/(n^2+n),求an已知数列{a}满足a1=1/2,a(n+1)=an+1/(n^2+n),求an