已知圆C:x^2+y^2-2x-2y+1=0,直线l:y=kx,且l与圆C交于P、Q两点,点M(0,b)满足MP⊥MQ.(1)当b=1时,求k的值;(2)若k>3,求b的取值范围.
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![已知圆C:x^2+y^2-2x-2y+1=0,直线l:y=kx,且l与圆C交于P、Q两点,点M(0,b)满足MP⊥MQ.(1)当b=1时,求k的值;(2)若k>3,求b的取值范围.](/uploads/image/z/5907879-63-9.jpg?t=%E5%B7%B2%E7%9F%A5%E5%9C%86C%3Ax%5E2%2By%5E2-2x-2y%2B1%3D0%2C%E7%9B%B4%E7%BA%BFl%3Ay%3Dkx%2C%E4%B8%94l%E4%B8%8E%E5%9C%86C%E4%BA%A4%E4%BA%8EP%E3%80%81Q%E4%B8%A4%E7%82%B9%2C%E7%82%B9M%EF%BC%880%2Cb%29%E6%BB%A1%E8%B6%B3MP%E2%8A%A5MQ.%281%29%E5%BD%93b%3D1%E6%97%B6%2C%E6%B1%82k%E7%9A%84%E5%80%BC%EF%BC%9B%EF%BC%882%EF%BC%89%E8%8B%A5k%EF%BC%9E3%2C%E6%B1%82b%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4.)
已知圆C:x^2+y^2-2x-2y+1=0,直线l:y=kx,且l与圆C交于P、Q两点,点M(0,b)满足MP⊥MQ.(1)当b=1时,求k的值;(2)若k>3,求b的取值范围.
已知圆C:x^2+y^2-2x-2y+1=0,直线l:y=kx,且l与圆C交于P、Q两点,点M(0,b)满足MP⊥MQ.
(1)当b=1时,求k的值;
(2)若k>3,求b的取值范围.
已知圆C:x^2+y^2-2x-2y+1=0,直线l:y=kx,且l与圆C交于P、Q两点,点M(0,b)满足MP⊥MQ.(1)当b=1时,求k的值;(2)若k>3,求b的取值范围.
(1)当b=1时,点M在圆上,又MP垂直MQ,所以直线l经过圆心.将圆心坐标
(1,1)代人L的方程,得:k=1
(2)
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