解不等式组3(x-2)+8>2x,(x+1)/3≤x-[(x-1)]/2,并求该不等式组最小整数解
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解不等式组3(x-2)+8>2x,(x+1)/3≤x-[(x-1)]/2,并求该不等式组最小整数解
解不等式组3(x-2)+8>2x,(x+1)/3≤x-[(x-1)]/2,并求该不等式组最小整数解
解不等式组3(x-2)+8>2x,(x+1)/3≤x-[(x-1)]/2,并求该不等式组最小整数解
3(x-2)+8>2x
∴ 3x-6+8>2x
∴ x>-2 ①
(x+1)/3≤x-[(x-1)]/2
2(x+1)≤6x-3(x-1)
∴ 2x+2≤6x-3x+3
∴ -x≤1
∴ x≥-1 ②
综上 x≥-1
∴ 满足该不等式组的最小整数解是-1
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