解关于x的不等式:㏒₂(x-1)>log₄[a(x-2)+1](a>0)
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/30 10:05:23
![解关于x的不等式:㏒₂(x-1)>log₄[a(x-2)+1](a>0)](/uploads/image/z/5580794-2-4.jpg?t=%E8%A7%A3%E5%85%B3%E4%BA%8Ex%E7%9A%84%E4%B8%8D%E7%AD%89%E5%BC%8F%EF%BC%9A%E3%8F%92%26%238322%3B%EF%BC%88x-1%EF%BC%89%EF%BC%9Elog%26%238324%3B%5Ba%EF%BC%88x-2%EF%BC%89%2B1%5D%EF%BC%88a%EF%BC%9E0%EF%BC%89)
解关于x的不等式:㏒₂(x-1)>log₄[a(x-2)+1](a>0)
解关于x的不等式:㏒₂(x-1)>log₄[a(x-2)+1](a>0)
解关于x的不等式:㏒₂(x-1)>log₄[a(x-2)+1](a>0)
㏒₂(x-1)=2log₄(x-1)=log₄[(x-1)^2]
所以原不等式即 log₄[(x-1)^2]>log₄[a(x-2)+1]
即[(x-1)^2]>[a(x-2)+1]
化简得(x-a)(x-2)>0
所以当a>2时,2