|x-2|+(y+1/4)^2=0 初一数学 速度……|x-2|+(y+1/4)^2=0,试求代数式x²(x²-xy+y)-x(x³-2x²+xy-1)的值已知xy²=-2,求-xy(x³y²-3x²y^5-y)的值
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![|x-2|+(y+1/4)^2=0 初一数学 速度……|x-2|+(y+1/4)^2=0,试求代数式x²(x²-xy+y)-x(x³-2x²+xy-1)的值已知xy²=-2,求-xy(x³y²-3x²y^5-y)的值](/uploads/image/z/5541499-19-9.jpg?t=%7Cx-2%7C%2B%28y%2B1%2F4%29%5E2%3D0+%E5%88%9D%E4%B8%80%E6%95%B0%E5%AD%A6+%E9%80%9F%E5%BA%A6%E2%80%A6%E2%80%A6%7Cx-2%7C%2B%28y%2B1%2F4%29%5E2%3D0%2C%E8%AF%95%E6%B1%82%E4%BB%A3%E6%95%B0%E5%BC%8Fx%26sup2%3B%EF%BC%88x%26sup2%3B%EF%BC%8Dxy%2By%EF%BC%89%EF%BC%8Dx%EF%BC%88x%26sup3%3B-2x%26sup2%3B%2Bxy%EF%BC%8D1%EF%BC%89%E7%9A%84%E5%80%BC%E5%B7%B2%E7%9F%A5xy%26sup2%3B%3D-2%2C%E6%B1%82%EF%BC%8Dxy%28x%26sup3%3By%26sup2%3B%EF%BC%8D3x%26sup2%3By%5E5%EF%BC%8Dy%EF%BC%89%E7%9A%84%E5%80%BC)
|x-2|+(y+1/4)^2=0 初一数学 速度……|x-2|+(y+1/4)^2=0,试求代数式x²(x²-xy+y)-x(x³-2x²+xy-1)的值已知xy²=-2,求-xy(x³y²-3x²y^5-y)的值
|x-2|+(y+1/4)^2=0 初一数学 速度……
|x-2|+(y+1/4)^2=0,试求代数式x²(x²-xy+y)-x(x³-2x²+xy-1)的值
已知xy²=-2,求-xy(x³y²-3x²y^5-y)的值
|x-2|+(y+1/4)^2=0 初一数学 速度……|x-2|+(y+1/4)^2=0,试求代数式x²(x²-xy+y)-x(x³-2x²+xy-1)的值已知xy²=-2,求-xy(x³y²-3x²y^5-y)的值
因为 |x-2| >=0 (y+1/4)^2>=0
|x-2|+(y+1/4)^2=0
所以|x-2|=0 (y+1/4)^2=0
x=2 y=-1/4
带入:x²(x²-xy+y)-x(x³-2x²+xy-1)=18