(1)函数y=cosx-sin^2x-cos2x+17/4的最小值是多少(2)小列函数中最小正周期为π的偶函数是?A.y=sin2x B.y=cosx/2 C.y=sin2x+cos2x D.y=1-tan^2/1+tan^2(3)设θ为第二象限角,则必有()A.tanθ/2>cotθ/2 B.tanθ/2cosθ
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![(1)函数y=cosx-sin^2x-cos2x+17/4的最小值是多少(2)小列函数中最小正周期为π的偶函数是?A.y=sin2x B.y=cosx/2 C.y=sin2x+cos2x D.y=1-tan^2/1+tan^2(3)设θ为第二象限角,则必有()A.tanθ/2>cotθ/2 B.tanθ/2cosθ](/uploads/image/z/5532379-43-9.jpg?t=%EF%BC%881%EF%BC%89%E5%87%BD%E6%95%B0y%3Dcosx-sin%5E2x-cos2x%2B17%2F4%E7%9A%84%E6%9C%80%E5%B0%8F%E5%80%BC%E6%98%AF%E5%A4%9A%E5%B0%91%EF%BC%882%EF%BC%89%E5%B0%8F%E5%88%97%E5%87%BD%E6%95%B0%E4%B8%AD%E6%9C%80%E5%B0%8F%E6%AD%A3%E5%91%A8%E6%9C%9F%E4%B8%BA%CF%80%E7%9A%84%E5%81%B6%E5%87%BD%E6%95%B0%E6%98%AF%3FA.y%3Dsin2x+B.y%3Dcosx%2F2+C.y%3Dsin2x%2Bcos2x+D.y%3D1-tan%5E2%2F1%2Btan%5E2%EF%BC%883%EF%BC%89%E8%AE%BE%CE%B8%E4%B8%BA%E7%AC%AC%E4%BA%8C%E8%B1%A1%E9%99%90%E8%A7%92%2C%E5%88%99%E5%BF%85%E6%9C%89%EF%BC%88%EF%BC%89A.tan%CE%B8%2F2%3Ecot%CE%B8%2F2+B.tan%CE%B8%2F2cos%CE%B8)
(1)函数y=cosx-sin^2x-cos2x+17/4的最小值是多少(2)小列函数中最小正周期为π的偶函数是?A.y=sin2x B.y=cosx/2 C.y=sin2x+cos2x D.y=1-tan^2/1+tan^2(3)设θ为第二象限角,则必有()A.tanθ/2>cotθ/2 B.tanθ/2cosθ
(1)函数y=cosx-sin^2x-cos2x+17/4的最小值是多少
(2)小列函数中最小正周期为π的偶函数是?
A.y=sin2x B.y=cosx/2 C.y=sin2x+cos2x D.y=1-tan^2/1+tan^2
(3)设θ为第二象限角,则必有()
A.tanθ/2>cotθ/2 B.tanθ/2cosθ/2 D.sinθ/2
(1)函数y=cosx-sin^2x-cos2x+17/4的最小值是多少(2)小列函数中最小正周期为π的偶函数是?A.y=sin2x B.y=cosx/2 C.y=sin2x+cos2x D.y=1-tan^2/1+tan^2(3)设θ为第二象限角,则必有()A.tanθ/2>cotθ/2 B.tanθ/2cosθ
1.y=cosx+sin^2x-cos2x+17\4
=cosx+1-cos^2x-(2cos^2x-1)+17\4
=-3cos^2x+cosx+25\4
=-3(cosx-1\6)^2+19\3
当cosx=-1时,ymin=9\4
2.D
A.y=sin2x T=2π\2=π 但是奇函数,所以A不正确.
B.y=cosx\2 T=2π\(1\2)=4π≠π 所以B不正确.
C.Y=sin2x+cos2x=√2sin(2x+π\4) T=2π\2=π 但是奇函数,所以C不正确.
因为ABC不正确,综上选D.
3.A C
2kπ+π\2cos150 所以选AC