若方程a²+2012a-1=0与b²+2012b-1=0,则a²b+ab²-ab=?1+1/a+1/b=?错了,是若方程a²+2012a-1=0与b²+2012b-1=0,则a²b+a²b-ab=?1+1/a+1/b=?
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/30 01:30:42
![若方程a²+2012a-1=0与b²+2012b-1=0,则a²b+ab²-ab=?1+1/a+1/b=?错了,是若方程a²+2012a-1=0与b²+2012b-1=0,则a²b+a²b-ab=?1+1/a+1/b=?](/uploads/image/z/5281139-11-9.jpg?t=%E8%8B%A5%E6%96%B9%E7%A8%8Ba%26%23178%3B%2B2012a-1%3D0%E4%B8%8Eb%26%23178%3B%2B2012b-1%3D0%2C%E5%88%99a%26%23178%3Bb%2Bab%26%23178%3B-ab%3D%3F1%2B1%2Fa%2B1%2Fb%3D%3F%E9%94%99%E4%BA%86%EF%BC%8C%E6%98%AF%E8%8B%A5%E6%96%B9%E7%A8%8Ba%26%23178%3B%2B2012a-1%3D0%E4%B8%8Eb%26%23178%3B%2B2012b-1%3D0%EF%BC%8C%E5%88%99a%26%23178%3Bb%2Ba%26%23178%3Bb-ab%3D%EF%BC%9F1%2B1%2Fa%2B1%2Fb%3D%EF%BC%9F)
若方程a²+2012a-1=0与b²+2012b-1=0,则a²b+ab²-ab=?1+1/a+1/b=?错了,是若方程a²+2012a-1=0与b²+2012b-1=0,则a²b+a²b-ab=?1+1/a+1/b=?
若方程a²+2012a-1=0与b²+2012b-1=0,则a²b+ab²-ab=?1+1/a+1/b=?
错了,是若方程a²+2012a-1=0与b²+2012b-1=0,则a²b+a²b-ab=?1+1/a+1/b=?
若方程a²+2012a-1=0与b²+2012b-1=0,则a²b+ab²-ab=?1+1/a+1/b=?错了,是若方程a²+2012a-1=0与b²+2012b-1=0,则a²b+a²b-ab=?1+1/a+1/b=?
a²+2012a-1=0与b²+2012b-1=0
即a和b是方程x²+2012x-1=0的根
所以a+b=-2012
ab=-1
所以
a²b+ab²-ab=
=ab(a+b)-ab
=(-1)*(-2014)-(-1)
=2015
1+1/a+1/b=
=1+(a+b)/ab
=1+(-2014)/(-1)
=2015
a²+2012a-1=0
b²+2012b-1=0
即a和b是方程x²+2012x-1=0的根
所以a+b=-2012
ab=-1
所以
a²b+a²b-ab
=ab(b+a-1)
=-1x(-2012-1)
=2013
1+1/a+1/b
=1+(a+b)/ab
=1+(-2012)/(-1)
=2013