已知函数f(x)=sin(2x+π/6)+sin(2x—π/6)—cos2x+a(a为实数,属于R)化简得f(x)=2sin(2x-π/6)+a若x属于【π/4,π/2】时,F(x)的最小值是-2,求a
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![已知函数f(x)=sin(2x+π/6)+sin(2x—π/6)—cos2x+a(a为实数,属于R)化简得f(x)=2sin(2x-π/6)+a若x属于【π/4,π/2】时,F(x)的最小值是-2,求a](/uploads/image/z/5279547-3-7.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3Dsin%282x%2B%CF%80%2F6%29%2Bsin%282x%E2%80%94%CF%80%2F6%29%E2%80%94cos2x%2Ba%28a%E4%B8%BA%E5%AE%9E%E6%95%B0%2C%E5%B1%9E%E4%BA%8ER%29%E5%8C%96%E7%AE%80%E5%BE%97f%EF%BC%88x%EF%BC%89%3D2sin%EF%BC%882x%EF%BC%8D%CF%80%2F6%EF%BC%89%EF%BC%8Ba%E8%8B%A5x%E5%B1%9E%E4%BA%8E%E3%80%90%CF%80%2F4%2C%CF%80%2F2%E3%80%91%E6%97%B6%2CF%EF%BC%88x%29%E7%9A%84%E6%9C%80%E5%B0%8F%E5%80%BC%E6%98%AF-2%2C%E6%B1%82a)
已知函数f(x)=sin(2x+π/6)+sin(2x—π/6)—cos2x+a(a为实数,属于R)化简得f(x)=2sin(2x-π/6)+a若x属于【π/4,π/2】时,F(x)的最小值是-2,求a
已知函数f(x)=sin(2x+π/6)+sin(2x—π/6)—cos2x+a(a为实数,属于R)
化简得f(x)=2sin(2x-π/6)+a
若x属于【π/4,π/2】时,F(x)的最小值是-2,求a
已知函数f(x)=sin(2x+π/6)+sin(2x—π/6)—cos2x+a(a为实数,属于R)化简得f(x)=2sin(2x-π/6)+a若x属于【π/4,π/2】时,F(x)的最小值是-2,求a
你都会已经化简了,
最小值在π/4取到,此时2x-π/6=5π/6,f(π/4) = 1+a = -2,a = -3
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