若等腰三角形的顶角为X,则它腰上的高与底边的夹角等于A.90-XB.(90-X)除以2C.90-2分之XD.2分之X
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![若等腰三角形的顶角为X,则它腰上的高与底边的夹角等于A.90-XB.(90-X)除以2C.90-2分之XD.2分之X](/uploads/image/z/5277592-64-2.jpg?t=%E8%8B%A5%E7%AD%89%E8%85%B0%E4%B8%89%E8%A7%92%E5%BD%A2%E7%9A%84%E9%A1%B6%E8%A7%92%E4%B8%BAX%2C%E5%88%99%E5%AE%83%E8%85%B0%E4%B8%8A%E7%9A%84%E9%AB%98%E4%B8%8E%E5%BA%95%E8%BE%B9%E7%9A%84%E5%A4%B9%E8%A7%92%E7%AD%89%E4%BA%8EA.90-XB.%2890-X%29%E9%99%A4%E4%BB%A52C.90-2%E5%88%86%E4%B9%8BXD.2%E5%88%86%E4%B9%8BX)
若等腰三角形的顶角为X,则它腰上的高与底边的夹角等于A.90-XB.(90-X)除以2C.90-2分之XD.2分之X
若等腰三角形的顶角为X,则它腰上的高与底边的夹角等于
A.90-X
B.(90-X)除以2
C.90-2分之X
D.2分之X
若等腰三角形的顶角为X,则它腰上的高与底边的夹角等于A.90-XB.(90-X)除以2C.90-2分之XD.2分之X
底角=(180-x)/2
腰上的高与底边的夹角=180-90-底角=x/2
B
DDDDDDD
等腰三角形ABC,顶点是A,剩下两点是B和C,腰上的高交AB与点D
顶角X,底角=2分之(180-X),即90-2分之X.在三角形BCD中,角D=90,角B=底角=90-2分之X,根据三角形内角和180,所以角C=90-(90-2分之X),即2分之X.角C就是腰上的高与底边的夹角,故选DDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDD...
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DDDDDDD
等腰三角形ABC,顶点是A,剩下两点是B和C,腰上的高交AB与点D
顶角X,底角=2分之(180-X),即90-2分之X.在三角形BCD中,角D=90,角B=底角=90-2分之X,根据三角形内角和180,所以角C=90-(90-2分之X),即2分之X.角C就是腰上的高与底边的夹角,故选DDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDD
收起
D,不选D我不是人
D