诺a,b,c为△ABC的三边,且(a²-2ab+b²)+(b²-2bc+c²)=0,是说明△ABC的形状急,
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![诺a,b,c为△ABC的三边,且(a²-2ab+b²)+(b²-2bc+c²)=0,是说明△ABC的形状急,](/uploads/image/z/5201061-69-1.jpg?t=%E8%AF%BAa%2Cb%2Cc%E4%B8%BA%E2%96%B3ABC%E7%9A%84%E4%B8%89%E8%BE%B9%2C%E4%B8%94%28a%26%23178%3B-2ab%2Bb%26%23178%3B%29%2B%28b%26%23178%3B-2bc%2Bc%26%23178%3B%29%3D0%2C%E6%98%AF%E8%AF%B4%E6%98%8E%E2%96%B3ABC%E7%9A%84%E5%BD%A2%E7%8A%B6%E6%80%A5%2C)
诺a,b,c为△ABC的三边,且(a²-2ab+b²)+(b²-2bc+c²)=0,是说明△ABC的形状急,
诺a,b,c为△ABC的三边,且(a²-2ab+b²)+(b²-2bc+c²)=0,是说明△ABC的形状
急,
诺a,b,c为△ABC的三边,且(a²-2ab+b²)+(b²-2bc+c²)=0,是说明△ABC的形状急,
(a²-2ab+b²)+(b²-2bc+c²)=0
(a-b)²+(b-c)²=0
即a=b,b=c
a=b=c
三角形是等边三角形